PHP类型提示以允许Array或ArrayAccess

问题描述

是否可以允许Array或实现ArrayAccess的对象?

Is it possible to allow an Array or an object that implements ArrayAccess?

例如:

class Config implements ArrayAccess {
    ...
}

class I_Use_A_Config
{
    public function __construct(Array $test)
    ...
}

我希望能够传递Array或ArrayAccess.

I want to be able to pass in either an Array or ArrayAccess.

除了手动检查参数类型外，还有一种干净的方法吗?

Is there a clean way to do this other than manually checking the parameter type?

推荐答案

不，没有干净"的方法.

No, there is no "clean" way of doing it.

array类型是原始类型.实现ArrayAccess接口的对象基于类，也称为复合类型.没有包含这两者的类型提示.

The array type is a primitive type. Objects that implement the ArrayAccess interface are based on classes, also known as a composite type. There is no type-hint that encompasses both.

由于您将ArrayAccess用作数组，因此可以将其强制转换.例如:

Since you are using the ArrayAccess as an array you could just cast it. For example:

$config = new Config;
$lol = new I_Use_A_Config( (array) $config);

如果这不是一个选项(您想按原样使用Config对象)，则只需删除类型提示并检查它是否为数组或ArrayAccess.我知道您想避免这种情况，但这没什么大不了的.只是几行，而当一切都说完之后，就没什么了.

If that is not an option (you want to use the Config object as it is) then just remove the type-hint and check that it is either an array or an ArrayAccess. I know you wanted to avoid that but it is not a big deal. It is just a few lines and, when all is said and done, inconsequential.

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