如何使用 Node.js 获取当前脚本的路径?

问题描述

如何在 Node.js 中获取脚本的路径?

How would I get the path to the script in Node.js?

我知道有 process.cwd，但这仅指调用脚本的目录，而不是脚本本身.例如，假设我在 /home/kyle/ 并运行以下命令:

I know there's process.cwd, but that only refers to the directory where the script was called, not of the script itself. For instance, say I'm in /home/kyle/ and I run the following command:

node /home/kyle/some/dir/file.js

如果我调用 process.cwd()，我得到的是 /home/kyle/，而不是 /home/kyle/some/dir/.有没有办法得到那个目录?

If I call process.cwd(), I get /home/kyle/, not /home/kyle/some/dir/. Is there a way to get that directory?

推荐答案

我再次浏览文档后找到了它.我正在寻找的是 __filename和 __dirname 模块级变量.

I found it after looking through the documentation again. What I was looking for were the __filename and __dirname module-level variables.

• __filename 是当前模块的文件名.这是当前模块文件的解析绝对路径.(例如:/home/kyle/some/dir/file.js)
• __dirname 是当前模块的目录名.(例如:/home/kyle/some/dir)

• __filename is the file name of the current module. This is the resolved absolute path of the current module file. (ex:/home/kyle/some/dir/file.js)
• __dirname is the directory name of the current module. (ex:/home/kyle/some/dir)

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