问题描述
在 Tkinter 中,我们有时必须创建对转换后的图像(例如),以便它在超出范围时不会被销毁.
一种常见的方法是向其小部件实例添加一个变量.一个例子是:
bard = Image.open("bardejov.jpg")bardejov = ImageTk.PhotoImage(bard)标签1 = 标签(自我,图像=bardejov)label1.image = bardejov #<<<<<<<<<<<<<<<<<<label1.place(x=20, y=20)
这是 Zetcode 的 Jan Bodnar 发布的示例的一部分,我对该示例进行了标记.bardejov 是函数中的局部变量,如果注释掉标记的那行就得不到图像,因为函数返回时它被销毁了,标签只看到'none'.
我是 Tkinter 的新手,这让我很担心,向系统代码添加新属性,有人建议这样做:
类 S():# 使对象可访问",从而保存# 它来自垃圾收集.弗雷德 = []@类方法定义保存(cls,x):cls.fred.append(x)
这在 Jan 的例子中确实有效:
bard = Image.open("xxxx.jpg")bardejov = ImageTk.PhotoImage(bard)标签1 = 标签(自我,图像=bardejov)#label1.image = bardejovS.save(bardejov)
但是可以吗?有什么不良副作用吗?
这不是问题,好不好,你必须去做.
您可以定义自己的 PhotoImageLabel
,而不是一遍又一遍地重复.
例如:
导入 tkinter 作为 tk从 PIL 导入 Image、ImageTk类 PhotoImageLabel(tk.Label):def __init__(self, parent, **kwargs):image = Image.open(kwargs['image'])self._image = ImageTk.PhotoImage(image)kwargs['image'] = self._imagesuper().__init__(parent, **kwargs)
用法:
类应用程序(tk.Tk):def __init__(self):super().__init__()self.photo_label = PhotoImageLabel(self, image="xxxx.jpg")self.photo_label.grid()如果 __name__ == '__main__':应用程序().主循环()
评论:总有一天我想小部件本身会解决这个问题
这不太可能,因为 ImageTk.PhotoImage
不是 tkinter
的一部分.您可以通过将图像对象绑定到小部件来扩展 PhotoImage
使其表现得像一个 tkinter
对象:
例如:
class PhotoImage(ImageTk.PhotoImage):def __init__(self, parent, **kwargs):图像 = kwargs['图像']# PIL.Image =>.PhotoImagesuper().__init__(image)# 更新 <widget>.children 为 [self.__photo.name] = selfself._ref = parent.childrenself._ref[self.__photo.name] = selfdef销毁(自我):# 这在父级`.destroy()` 上被调用# 删除parent.children中的引用del self._ref[self.__photo.name]
用法:
class PhotoImageLabel(tk.Label):def __init__(self, parent, **kwargs):image = Image.open(kwargs['image'])# 获取一个绑定到'self'的PhotoImage对象kwargs['image'] = PhotoImage(self, image=image)super().__init__(parent, **kwargs)
In Tkinter, we sometimes have to create a reference toa converted image (for example), so that it will not be destroyed when it goes out of scope.
A common way is to add a variable to its widget instance. An example of this is:
bard = Image.open("bardejov.jpg")
bardejov = ImageTk.PhotoImage(bard)
label1 = Label(self, image=bardejov)
label1.image = bardejov #<<<<<<<<<<<<<<<<<<<<<
label1.place(x=20, y=20)
This is part of an example published by Jan Bodnar of Zetcode, with my flagging of the example. bardejov is a local variable in a function, and if you comment out the marked line you don't get the image, because it is destroyed when the function returns, and the label just sees 'none'.
I'm new to Tkinter, and this worried me rather, adding new properties to system code, and someone suggested this:
class S():
# To make an object 'accessible', and thus save
# it from garbage collection.
fred = []
@classmethod
def save(cls, x):
cls.fred.append(x)
This certainly worked in Jan's example:
bard = Image.open("xxxx.jpg")
bardejov = ImageTk.PhotoImage(bard)
label1 = Label(self, image=bardejov)
#label1.image = bardejov
S.save(bardejov)
But is it OK? Any undesirable side effects?
It's not the question, good or not, you have to do it.
Instead of doing it over and over again you can define your own PhotoImageLabel
.
For example:
import tkinter as tk
from PIL import Image, ImageTk
class PhotoImageLabel(tk.Label):
def __init__(self, parent, **kwargs):
image = Image.open(kwargs['image'])
self._image = ImageTk.PhotoImage(image)
kwargs['image'] = self._image
super().__init__(parent, **kwargs)
class App(tk.Tk):
def __init__(self):
super().__init__()
self.photo_label = PhotoImageLabel(self, image="xxxx.jpg")
self.photo_label.grid()
if __name__ == '__main__':
App().mainloop()
That is unlikely, because ImageTk.PhotoImage
is not part of tkinter
.You can extend PhotoImage
to behave it like a tkinter
object, by binding the image object to the widget:
For example:
class PhotoImage(ImageTk.PhotoImage):
def __init__(self, parent, **kwargs):
image = kwargs['image']
# PIL.Image => .PhotoImage
super().__init__(image)
# Update <widget>.children with [self.__photo.name] = self
self._ref = parent.children
self._ref[self.__photo.name] = self
def destroy(self):
# This gets called on `.destroy()` the parent
# Delete the reference in parent.children
del self._ref[self.__photo.name]
class PhotoImageLabel(tk.Label):
def __init__(self, parent, **kwargs):
image = Image.open(kwargs['image'])
# Get a PhotoImage object which is bound to 'self'
kwargs['image'] = PhotoImage(self, image=image)
super().__init__(parent, **kwargs)
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