Angular 5删除特定的DOM元素

问题描述

我有一个小问题，我不知道该怎么办.我只是在学习Angular/Typescript，我不知道如何删除一些DOM元素.我有一些自动生成的内容，其中包含特定的CSS类.不幸的是，这些对象是在其他地方生成的，我无法以任何方式对其进行配置，因此无法在该内容上添加任何ngIf或其他任何内容，这将简化我的工作……我只需要使用它们.我想要实现的是这样的(jQuery版本):

I have a small issue that I can't figure out how to do. I am just learning Angular / Typescript and I can't figure out how I could remove some DOM elements.I have some auto generated content, that has specific CSS classes. Unfortunately The objects are generated somewhere else and I cannot configure them in any way so I cannot add any ngIf or anything else on that content, that would simplify my work... I just have to use them.What I want to achieve is something like this( jQuery version):

$("#button").click(function() {
    $('.fc-oss').toggle();
 });

我有一个切换开关，我想附加一个事件，当它被激活时，它将在视图中隐藏/显示具有该特定类型的所有元素.我试图在没有jQuery的情况下实现此目标，但收效甚微.关于如何实现这一目标的任何想法吗?

I have a toggle and I want to attach an event to it that when it's being activated, it hides/ shows all elements with that specific type from the view. I am trying to achieve this in angular without jQuery but with little success. Any ideas on how I might be able to achieve this ?

推荐答案

在Angular中，您可以直接访问DOCUMENT.

In Angular you can use direct access to DOCUMENT.

import { Inject, Injectable } from '@angular/core';
import { DOCUMENT } from '@angular/platform-browser';

@Injectable()
export class MyService {
  constructor(@Inject(DOCUMENT) private document: any) {}
}

有了这个，您可以访问您的元素并为其定义一些逻辑

Having this you can access your element and define some logic to it

let element = this.document.getElementbyClassName('fc-oss');
element.style.display = element.style.display === 'none' ? 'block' : 'none';

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