在Android编写XML

问题描述

由于 org.w3c.dom.Document中的实例，我怎么它的内容保存到一个文件/流？

Given an instance of org.w3c.dom.Document, how do I save its contents to a file/stream?

编辑：正如CommonsWare指出，有没有这种可能使用的类Android SDK中之前的Andr​​oid 2.2（API 8）。你能推荐那么第三方库保存文件内容保存到一个文件/流？

As CommonsWare pointed out, there's no such possibility using classes from Android SDK prior to Android 2.2 (API 8). Can you recommend then a third-party library for saving Document contents to a file/stream?

推荐答案

您可以编写XML像所有其他的文本文件。对于解析文档字符串我用：

You can write xml like all others text files.For parsing Document to string I used:

public static String getStringFromNode(Node root) throws IOException {

        StringBuilder result = new StringBuilder();

        if (root.getNodeType() == 3)
            result.append(root.getNodeValue());
        else {
            if (root.getNodeType() != 9) {
                StringBuffer attrs = new StringBuffer();
                for (int k = 0; k < root.getAttributes().getLength(); ++k) {
                    attrs.append(" ").append(
                            root.getAttributes().item(k).getNodeName()).append(
                            "=\"").append(
                            root.getAttributes().item(k).getNodeValue())
                            .append("\" ");
                }
                result.append("<").append(root.getNodeName()).append(" ")
                        .append(attrs).append(">");
            } else {
                result.append("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
            }

            NodeList nodes = root.getChildNodes();
            for (int i = 0, j = nodes.getLength(); i < j; i++) {
                Node node = nodes.item(i);
                result.append(getStringFromNode(node));
            }

            if (root.getNodeType() != 9) {
                result.append("</").append(root.getNodeName()).append(">");
            }
        }
        return result.toString();
    }

但还有一个更简单的方法来做到这一点：http://www.ibm.com/developerworks/opensource/library/x-android/index.html#list11

But there is one more simple way to do this:http://www.ibm.com/developerworks/opensource/library/x-android/index.html#list11

private String writeXml(List<Message> messages){
    XmlSerializer serializer = Xml.newSerializer();
    StringWriter writer = new StringWriter();
    try {
        serializer.setOutput(writer);
        serializer.startDocument("UTF-8", true);
        serializer.startTag("", "messages");
        serializer.attribute("", "number", String.valueOf(messages.size()));
        for (Message msg: messages){
            serializer.startTag("", "message");
            serializer.attribute("", "date", msg.getDate());
            serializer.startTag("", "title");
            serializer.text(msg.getTitle());
            serializer.endTag("", "title");
            serializer.startTag("", "url");
            serializer.text(msg.getLink().toExternalForm());
            serializer.endTag("", "url");
            serializer.startTag("", "body");
            serializer.text(msg.getDescription());
            serializer.endTag("", "body");
            serializer.endTag("", "message");
        }
        serializer.endTag("", "messages");
        serializer.endDocument();
        return writer.toString();
    } catch (Exception e) {
        throw new RuntimeException(e);
    }
}

这篇关于在Android编写XML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！