的平面列表填充树视图

的平面列表填充树视图

本文介绍了如何根据具有“级别”的平面列表填充树视图?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个从第三方项目文件填充的对象列表。这个文件的设计方式是每个项目都在层次结构的层次上。所以第一个项目是0级,所有的子项都在1级,等等。



举个例子:

  1.节点1(级别0)
2.节点1.1(级别1)
3.节点1.2(级别1)
4.节点1.3(级别1)
5.节点1.3.1(级别2)
6.节点1.4(级别1)
7.节点2(级别0)
8.节点2.1(1级)
9.节点2.1.1(级别2)
10.节点3(级别0)
pre>

这将产生如下所示的层次结构:

   - 节点1 
---节点1.1
---节点1.2
---节点1.3
-----节点1.3.1
---节点1.4
- 节点2
---节点2.1
-----节点2.1.1
- 节点3

我的问题是找出如何根据这些级别属性将此结构填充到VCL TTreeView 每个列出的对象。如果我设计了这个第三方文件结构,我将使用一个父属性而不是一个level属性。



此列表中的对象可以像这样迭代: / p>

  var 
I:TMyItem;
N:TTreeNode;
begin
for X:= 0 to MyList.Count - 1 do begin
I:= MyList [X];
// TMyItem具有属性Level,它指定层次结构
//以及节点标题的Title属性
//如何基于Level创建节点?

N.Data:= I;
结束
结束

基于此结构,我如何在树视图中填充这个结构?

解决方案

尝试如下:

  var 
项目:TMyItem;
节点:TTreeNode;
NodeLevel:Integer;
X:整数;
begin
Node:= nil;
NodeLevel:= 0;
for X:= 0 to MyList.Count-1 do
begin
Item:= MyList [X];
if(Node = nil)或(Item.Level< = 0)then
begin
Node:= TreeView1.Items.AddObject(nil,Item.Text,Item);
NodeLevel:= 0;
end
else如果Item.Level = NodeLevel then
begin
Node:= TreeView1.Items.AddObject(Node,Item.Text,Item);
end else
begin
而Item.Level< = NodeLevel do
begin
Node:= Node.Parent;
Dec(NodeLevel);
结束
Node:= TreeView1.Items.AddChildObject(Node,Item.Text,Item);
Inc(NodeLevel);
结束
//根据需要设置Node属性...
end;
结束


I have a list of objects populated from a third-party project file. The way this file was designed is so each item is on a "level" of hierarchy. So the very first item is on level 0, all of its child items are on level 1, and so on.

As an example:

  1. Node 1     (Level 0)
  2. Node 1.1   (Level 1)
  3. Node 1.2   (Level 1)
  4. Node 1.3   (Level 1)
  5. Node 1.3.1 (Level 2)
  6. Node 1.4   (Level 1)
  7. Node 2     (Level 0)
  8. Node 2.1   (Level 1)
  9. Node 2.1.1 (Level 2)
 10. Node 3     (Level 0)

This would produce a hierarchy like so:

- Node 1
--- Node 1.1
--- Node 1.2
--- Node 1.3
----- Node 1.3.1
--- Node 1.4
- Node 2
--- Node 2.1
----- Node 2.1.1
- Node 3

My issue is figuring out how to populate this structure into a VCL TTreeView based on these "Level" properties of each listed object. If I had designed this third-party file structure, I would have used a parent property instead of a level property.

Objects in this list can be iterated like this:

var
  I: TMyItem;
  N: TTreeNode;
begin
  for X := 0 to MyList.Count - 1 do begin
    I := MyList[X];
    //TMyItem has property "Level" which specifies hierarchy
    //  as well as "Title" property for the node's caption
    //How to create node based on Level?

    N.Data := I;
  end;
end;

Based on this structure, how do I populate this in a tree view?

解决方案

Try something like this:

var
  Item: TMyItem;
  Node: TTreeNode;
  NodeLevel: Integer;
  X: Integer;
begin
  Node := nil;
  NodeLevel := 0;
  for X := 0 to MyList.Count-1 do
  begin
    Item := MyList[X];
    if (Node = nil) or (Item.Level <= 0) then
    begin
      Node := TreeView1.Items.AddObject(nil, Item.Text, Item);
      NodeLevel := 0;
    end
    else if Item.Level = NodeLevel then
    begin
      Node := TreeView1.Items.AddObject(Node, Item.Text, Item);
    end else
    begin
      while Item.Level <= NodeLevel do
      begin
        Node := Node.Parent;
        Dec(NodeLevel);
      end;
      Node := TreeView1.Items.AddChildObject(Node, Item.Text, Item);
      Inc(NodeLevel);
    end;
    // set Node properties as needed...
  end;
end;

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09-02 00:07