C ++表示1D数组中的3D数组

问题描述

我想在一个1D数组中为每个3D坐标以像素阵列存储aFloat的字节值：

float aFloat = 1.0;
unsigned char * pixelsArray = new unsigned char [HEIGHT * WIDTH * 3];

for（int i = 0; i {
for（int j = 0; j< WIDTH; j ++）

for（int k = 0; k {
pixelsArray [？] = aFloat;
}
}
}


？我认为如果我没有错误，它还需要 + sizeof（float）在索引的某个地方。

解决方案

您的内线需要：

  pixelsArray [（i * WIDTH + j ）* 3 + k] =（unsigned char）（255.0 * aFloat）; 
  

这应该会给你一个全白的图像。

确保你的目标实际上是每个像素三个字节，而不是四个（alpha通道或填充）;如果是四，您只需要将上面的 3 更改为 4 。

I want to store the byte value of aFloat in pixelsArray for each 3D coordinate, in a 1D array:

float aFloat = 1.0;
unsigned char* pixelsArray = new unsigned char[HEIGHT*WIDTH*3];

for (int i = 0; i < HEIGHT; i++)
{
   for (int j = 0; j < WIDTH; j++)
   {
      for (int k = 0; k < 3; k++)
      {
         pixelsArray[?] = aFloat;
      }
   }
}

What would go in the ?? I think it also needs to have + sizeof(float) somewhere in the index if I'm not mistaken.

解决方案

Your inside line needs to be:

pixelsArray[(i * WIDTH + j) * 3 + k] = (unsigned char)(255.0 * aFloat);

This should give you an all-white image.

Make sure your target is really three bytes per pixel and not four (alpha channel or padding); if it is four, you'll just need to change the 3 above to a 4.

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