问题描述
我在UITableView中使用UIRefreshControl:
I use UIRefreshControl in a UITableView:
UIRefreshControl *refreshControl = [[UIRefreshControl alloc] init];
[refreshControl addTarget:self action:@selector(refresh)
forControlEvents:UIControlEventValueChanged];
self.refreshControl = refreshControl;
带有刷新处理程序:
-(void)refresh {
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
// (...some long running operation...)
dispatch_async(dispatch_get_main_queue(), ^{
[self.refreshControl endRefreshing];
});
});
}
在长时间运行的操作中,我按下Home按钮使应用程序处于非活动状态。之后,我再次使该应用程序处于活动状态。旋转器冻结(停止旋转),无法将其恢复到初始状态。
During the long running operation I make the application inactive pressing Home button. After that I make the application active again. The spinner freezes (stops spinning) and there is no way to return it to the initial state.
如何解决?
推荐答案
我认为答案有点延迟,但是,今天我在ios 7上看到了类似的问题,ios 6继续旋转,
I think it is a bit delayed answer but , today I saw similar issue on ios 7 , ios 6 continued spinning ,
这里有一些解决方法
- (void)viewWillAppear:(BOOL)animated {
[super viewWillAppear:animated];
if(self.refreshControl.isRefreshing) {
CGPoint offset = self.tableView.contentOffset;
[self.refreshControl endRefreshing];
[self.refreshControl beginRefreshing];
self.tableView.contentOffset = offset;
}
}
它将停止并再次开始旋转,但仅发生在ios7上,所以也许我应该在ios6上不要这么做
it will stop and start again spinning , but it only happened on ios7 with me , so maybe you should check not to do it on ios6
- (void)viewWillAppear:(BOOL)animated {
[super viewWillAppear:animated];
if(self.refreshControl.isRefreshing && [[[UIDevice currentDevice] systemVersion] floatValue] >= 7) {
CGPoint offset = self.tableView.contentOffset;
[self.refreshControl endRefreshing];
[self.refreshControl beginRefreshing];
self.tableView.contentOffset = offset;
}
}
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