问题描述
最近,我了解到类实现了对键的二进制搜索,我想以此为自己的优势。我正在制作一个线性函数类,它表示一堆线的集合
Recently, I learned that the Sorted Dictionary class implements binary search over the keys, and I wanted to use this to my advantage. I am making a piecewise linear function class that represents a collection of lines over a bunch of intervals.
我定义了一个 Interval
类,如下所示:
I defined an Interval
class like this:
public class Interval : ICloneable, IComparable, IComparable<Interval>
{
public Interval()
{
}
public Interval(double start, double end)
{
Start = start;
End = end;
}
// Properties
public double Start { get; set; } = double.NaN;
public double End { get; set; } = double.NaN;
public double Span => End - Start;
// Methods
public object Clone() => MemberwiseClone();
public int CompareTo(object obj)
{
return Start.CompareTo(obj);
}
public int CompareTo([AllowNull] Interval other)
{
if (Start < other.Start)
{
return -1;
}
else if (Start > other.Start)
{
return 1;
}
else
{
return 0;
}
}
public bool Contains(double x) => Start <= x && x <= End;
public override string ToString() => $"[{Start}, {End}]";
}
问题中的 SortedDictionary
的工作原理如下这在分段函数类中:
And the SortedDictionary
in question works like this in the piecewise function class:
public class PiecewiseLinearFunction : ICloneable
{
...
// The dictionary
public SortedDictionary<Interval, Line2D> Functions { get; set; } = new SortedDictionary<Interval, Line2D>(); // Where Line2D is just a class that contains a function definition for a line
// Methods
public Interval FindInterval(double x)
=> Functions.Keys.Where(interval => interval.Contains(x)).FirstOrDefault();
public double Solve(double x)
{
var interval = FindInterval(x);
if (interval != null && Functions.ContainsKey(interval))
{
return Functions[interval].Solve(x);
}
else
{
return double.NaN;
}
}
}
如您所见, PiecewiseLinearFunction.FindInterval(double x)
方法线性搜索字典的键,以查找包含(或不包含) x $ c的间隔$ c>,它可以用于二进制查找,但是显然完全违背了进行二进制查找的目的。
So as you can see, the PiecewiseLinearFunction.FindInterval(double x)
method linearly searches through the dictionary's keys in order to find the interval that contains (or doesn't contain) x
, which can be used for binary look-up, but that obviously defeats the purpose of doing the binary look-up at all.
我想知道是否可以通过某种方式进行字典会查找 double x
值,并在间隔上进行二进制搜索,同时检查 Interval.Contains(double x)
为 true
或 false
是要确定是否存在有效的间隔(键)和相应的行,用来获取 x
处的函数值。
I was wondering if I could somehow make the dictionary look up the double x
value instead, and do a binary search over the intervals while checking if Interval.Contains(double x)
is true
or false
to decide if there is a valid interval (key) and a corresponding line that can be used to get the function value at x
.
换句话说,是否可以使用谓词进行搜索,例如 FindInterval(double x)=> Functions.Keys.FindBinary(i => i.Contains(x))
。
In other words, is there a way to search with a predicate, something like FindInterval(double x) => Functions.Keys.FindBinary(i => i.Contains(x))
.
推荐答案
因此,如果间隔不重叠,则实际上实际上不需要自定义二进制搜索。
So if the intervals don't overlap there is actually not really a need for a custom binary search.
首先,如果我们使 Interval
相当于 double
:
First of all it helps if we make Interval
comparable to double
:
public class Interval: IComparable<double>
{
public double Start { get; set; }
public double End { get; set; }
public bool Contains(double x) => x >= Start && x <= End;
public int CompareTo(double other)
{
if (Contains(other))
return 0;
return other < Start ? 1 : -1;
}
}
现在我们创建一个 List
扩展名,因此我们能够使用其他类型(而不仅仅是列表类型)进行二进制搜索:
Now we create a List
extension so we're able to do binary search with other types then just the type of the list:
public static class ListExtensions
{
public static int BinarySearch<T, TU>(this List<T> sortedSource, TU val) where T : IComparable<TU>
{
return sortedSource.BinarySearch(default(T), Comparer<T>.Create((item, _) => item.CompareTo(val)));
}
}
现在我们可以像这样测试它了:
And now we can test it like this:
var list = new List<Interval>
{
new Interval
{
Start = 0,
End = 4
},
new Interval
{
Start = 6,
End = 7
},
new Interval
{
Start = 10,
End = 12
}
};
var index = list.BinarySearch(6.0d); //index = 1
var interval = index < 0 ? null : list[index]; //interval = [6, 7]
index = list.BinarySearch(9.0d); //index = -3
interval = index < 0 ? null : list[index]; //interval = null
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