问题描述
当 args 参数作为序列给出时,我遇到了 subprocess.Popen 问题.
I'm having a problem with subprocess.Popen when args parameter is given as sequence.
例如:
import subprocess
maildir = "/home/support/Maildir"
这有效(它打印/home/support/Maildir 目录的正确大小):
This works (it prints the correct size of /home/support/Maildir dir):
size = subprocess.Popen(["du -s -b " + maildir], shell=True,
stdout=subprocess.PIPE).communicate()[0].split()[0]
print size
但是,这不起作用(试试看):
But, this doesn't work (try it):
size = subprocess.Popen(["du", "-s -b", maildir], shell=True,
stdout=subprocess.PIPE).communicate()[0].split()[0]
print size
怎么了?
推荐答案
来自 文档
在 Unix 上,shell=True: […] 如果 args 是一个序列,则第一项指定命令字符串和任何 附加项将被视为附加参数外壳本身.也就是说,Popen 的作用相当于:
Popen(['/bin/sh', '-c', args[0], args[1], ...])
这在您的情况下翻译为:
Which translates in your case to:
Popen(['/bin/sh', '-c', 'du', '-s', '-b', maildir])
这意味着 -s
、-b
和 maildir
被 shell 解释为选项,而不是 du代码>(在 shell 命令行上试试!).
This means that -s
, -b
and maildir
are interpreted as options by the shell, not by du
(try it on the shell commandline!).
由于在您的情况下不需要 shell=True
,因此您可以将其删除:
Since shell=True
is not needed in your case anyway, you could just remove it:
size = subprocess.Popen(['du', '-s', '-b', maildir],
stdout=subprocess.PIPE).communicate()[0].split()[0]
或者,您可以只使用原始方法,但在这种情况下您不需要列表.您还必须注意目录名称中的空格:
Alternatively you could just use your orignal approach, but you don't need a list in that case. You would also have to take care of spaces in the directory name:
size = subprocess.Popen('du -s -b "%s"' % maildir, shell=True,
stdout=subprocess.PIPE).communicate()[0].split()[0]
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