本文介绍了在单击事件的Android窗口小部件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在android的创建部件并将其成功的作品,但现在我想用小窗口的单击事件,这样我可以从打开新的活动。
帮助我
解决方案
@覆盖
公共无效的OnUpdate(上下文的背景下,AppWidgetManager appWidgetManager,
INT [] appWidgetIds){
的for(int i = 0; I< appWidgetIds.length;我++){
INT appWidgetId = appWidgetIds [I]
意向意图=新的意图(背景下,TaskManagerActivity.class);
PendingIntent pendingIntent = PendingIntent.getActivity(上下文,0,意图,0);
RemoteViews意见=新RemoteViews(context.getPackageName(),R.layout.widget);
views.setOnClickPendingIntent(R.id.widget_layout,pendingIntent);
appWidgetManager.updateAppWidget(appWidgetId,意见);
}
}
在widget.xml我有根元素的LinearLayout ID为widget_layout
< LinearLayout中的xmlns:机器人=http://schemas.android.com/apk/res/android
机器人:ID =@ + ID / widget_layout
机器人:layout_width =FILL_PARENT
机器人:layout_height =FILL_PARENT
机器人:paddingTop =10dip
机器人:以下属性来=10dip
机器人:方向=垂直>
I have created widget in android and it successfully works, but now I want to use on click event of widget so that I can open new activity from that.
Help me
解决方案
@Override
public void onUpdate(Context context, AppWidgetManager appWidgetManager,
int[] appWidgetIds) {
for (int i = 0; i < appWidgetIds.length; i++) {
int appWidgetId = appWidgetIds[i];
Intent intent = new Intent(context, TaskManagerActivity.class);
PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0);
RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.widget);
views.setOnClickPendingIntent(R.id.widget_layout, pendingIntent);
appWidgetManager.updateAppWidget(appWidgetId, views);
}
}
In widget.xml I have root element LinearLayout with id widget_layout
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/widget_layout"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:paddingTop="10dip"
android:paddingLeft="10dip"
android:orientation="vertical">
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