让 after() 方法按时运行 Tkinter

问题描述

我正在编写一个工具，该工具必须使用 python 在 Tkinter 中显示精度为 1/100 秒的计时器.我尝试使用 after() 方法和 self.timerLabel.after(0, self.update_timer)

I'm programming a tool that has to display a timer with 1/100 of second as precision in Tkinter with python. I've tried using the after() method with self.timerLabel.after(0, self.update_timer)

def update_timer (self):
        self.timer += 0.01
        self.timerLabel.configure(text="%.2f" % self.timer)
        self.timerLabel.after(10, self.update_timer)

问题是它的运行速度比预期的要慢，我需要知道是否有解决方法或某种方法可以让计时器准确按时运行.或者也许是某种方式使用计算机的时间在屏幕上显示正确的经过时间.提前致谢

The problem is that it runs way slower than expected and I need to know if there's a workaround or some way to have the timer run exactly on time.Or maybe some way to use the computer's time to display the correct elapsed time on the screen.Thank you in advance

推荐答案

最准确的方法大概就是找一个开始时间，然后每次调用更新定时器函数就从当前时间减去开始时间.

The most accurate method is probably to find a start time, then every time you call the update timer function just subtract the start time from the current time.

>

我附上了一些示例代码，向您大致展示了它是如何工作的.调整它以将 after() 用于 Tkinter 应该相当简单.

I've attached some example code to show you roughly how it would work. It should be fairly simple to adapt that to use after() for Tkinter.

import time

# Start time
startTime = time.time();

def update_timer():

  # Find difference and print
  timeDifference = time.time() - startTime;
  print(timeDifference);

  # Sleep appropriate amount of time before printing
  # next statement.
  time.sleep(0.1);

  # Recursively call update.
  update_timer();

# Start running
update_timer();

示例小提琴:https://repl.it/Hoqh/0

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