问题描述
获取上下文，角度，ui-router，没什么特别的，一个用 3 个名为 ui-views 构建的根视图.所以在 index.html 我们有
Get the context, angular, ui-router, nothing special, a root view built with 3 named ui-views.so in index.html we have
<body>
<div ui-view='left'>
<div ui-view='center'>
<div ui-view='right'>
</body>
我的路线看起来像
$stateProvider
.state('main', {
url: '/',
views: {
'left': {templateUrl: 'foo.html'},
'center': {templateUrl: 'bar.html'},
'right': {templateUrl: 'xyz.html'}
}
})
.state('main.b', {
url: '/b',
params: { foo: {value: 'bar'} }
views: { 'right@': {templateUrl: '123.html'} } // I wish to update $stateParams in 'left@' view
})
.state('main.c', {
url: '/c',
params: ...
views: { 'left@': ..., 'center@': ..., 'right@': .. }
});
有没有办法去b状态更新'center'和'left'视图中的$stateParams??我可以使用服务获得它，但我需要将 $watch 添加到我需要的变量中，对我来说它看起来有点笨拙.
Is there a way in going to b state to update the $stateParams in the 'center' and 'left' view?? I can get it using a service but i need to add a $watch to the variable I need and it looks a little bit hacky to me.
进入 c 状态我实际上可以得到我想要的东西，但是视图被重新加载，我希望避免这种行为，因为我在左"视图中有一个画布.
Going into c state I can actually get what I want, but the view is reloaded, and i wish to avoid this behaviour cause i have a canvas in the 'left' view.
推荐答案
您可以使用以下内容转到特定路线而无需重新加载视图:
You could use the following to go to a specific route without reloading the views:
$state.go('.', {parm1: 1}, {notify: false});
最后一个对象字面量表示您可以传递给 go 的选项.如果您将 notify 设置为 false，这实际上会阻止控制器重新初始化.开头的 . 是你要去的绝对状态名或相对状态路径.
The last object literal represents the options which you can pass along to go. If you set notify to false, this will actually prevent the controllers from being reinitialized. The . at the beginning is the absolute state name or relative state path you wanna go to.
重要的是notify.
这篇关于如何在不重新加载 ui-view 的情况下更新 $stateParams?角度ui路由器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！