问题描述
我已经在我的应用中成功实现了Firebase消息传递.在后台运行良好,当应用程序在前台(yippee!)时,onMessageReceived()会被调用.
I have successfully implemented Firebase messaging in my app. Works great in the background and onMessageReceived() gets called when the app is in the foreground (yippee!).
我遇到的问题是,我需要动态更新UI,而我仍坚持实现这一目标的最佳方法.我不想向用户发送应用内通知(如示例代码所示),我不确定是否要发送广播,我要做的就是访问MainActivity以调用方法已经存在,但是我没有在服务中引用MainActivity.
The issue I have is that I need to update the UI dynamically and I am stuck on the best way to achieve this. I don't want to send the user an in-app notification (as the sample code shows), I'm not sure I want to send a broadcast, all I want to do is to access the MainActivity in order to call a method already there, however I have no reference to the MainActivity in the service.
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
if (remoteMessage.getNotification().getBody() != null) {
Log.d(LOG_TAG, "Message received: " + remoteMessage.getNotification().getBody());
} else {
Log.d(LOG_TAG, "Message received: " + remoteMessage.getData().get("message"));
}
// Call method in MainActivity
// <<< What goes Here?>>>>
}
这似乎是一个简单的用例,但我找不到任何在线帮助.
This seems a simple use case but I can't find anything online to help.
预先感谢
推荐答案
是的,您可以使用本地广播
在您的 onMessageReceived() Firebase服务中.
In your onMessageReceived() Firebase Service.
broadcaster = LocalBroadcastManager.getInstance(getBaseContext());
Intent intent = new Intent(REQUEST_ACCEPT);
intent.putExtra("Key", value);
intent.putExtra("key", value);
broadcaster.sendBroadcast(intent);
并在活动"或片段"方法中注册本地广播
and register local Broadcast in your Activity or fragment method
@Override
public void onStart() {
super.onStart();
LocalBroadcastManager.getInstance(getActivity()).registerReceiver((receiver),
new IntentFilter(PushNotificationService.REQUEST_ACCEPT)
);
}
@Override
public void onStop() {
super.onStop();
LocalBroadcastManager.getInstance(getActivity()).unregisterReceiver(receiver);
}
并处理这样的更新事件,在这里执行更新UI,当收到通知并onMessageReceived()发送广播时,它将自动调用.
and Handle Your update event like this, do your update UI work Here, it will call automatically when notification received and onMessageReceived() send a broadcast.
receiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
try {
String value= intent.getStringExtra("key");
String value= intent.getStringExtra("key");
} catch (Exception e) {
e.printStackTrace();
}
}
};
这篇关于Android Firebase消息传递:如何从onMessageReceived()更新UI的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!