问题描述
I want to mock a method of a class and execute a callback which modifies the object given as parameter (using PHP 5.3 with PHPUnit 3.5.5).
Let´s say I have the following class:
class A
{
function foobar($object)
{
doSomething();
}
}
And this setup code:
$mock = $this->getMockBuilder('A')->getMock();
$mock->expects($this->any())->method('foobar')->will(
$this->returnCallback(function($object) {
$object->property = something;
}));
For some reason the object does not get modified. On var_dump
ing $object
I see it is the right object. Could it be that the object gets passed by value? How can I configure the mock to receive a reference?
He Alex,
i talked to Sebastian (the phpunit creator) about that problem and yes: The argument gets clone
ed before it is passed to the callback.
From the top of my head i can't offer you any workaround but i choose to answer anyway to at least tell you that you are doing nothing wrong and that this is expected behavior.
To quote Sebastians comment on IRC on why it clones the argument:
To have something copy/pasteable:
Assertion 3 in this codesample will fail. (The variable is only changed in the returned object)
<?php
class A
{
function foobar($o)
{
$o->x = mt_rand(5, 100);
}
}
class Test extends PHPUnit_Framework_TestCase
{
public function testFoo()
{
$mock = $this->getMock('A');
$mock->expects($this->any())
->method('foobar')
->will($this->returnCallback(function($o) { $o->x = 2; return $o; }));
$o = new StdClass;
$o->x = 1;
$this->assertEquals(1, $o->x);
$return = $mock->foobar($o);
$this->assertEquals(2, $return->x);
$this->assertEquals(2, $o->x);
}
}
Update:
Starting with PHPUnit 3.7 the cloning can be turned off. See the last argument off:
public function getMock(
$originalClassName,
$methods = array(),
array $arguments = array(),
$mockClassName = '',
$callOriginalConstructor = TRUE,
$callOriginalClone = TRUE,
$callAutoload = TRUE,
$cloneArguments = FALSE
);
It might even be off by default :)
这篇关于在 PHPUnit Mocks 的 returnCallback() 中修改对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!