getValueAt()方法返回null

问题描述

我试图将defaulttablemodel的所有值保存到我的sql数据库中，但是每当我尝试通过table.valueAt()在最后插入的行上打印该值时，它都将返回null.

I am trying to save all the values of a defaulttablemodel to my sql database but whenever I put try to print the value on the last inserted row via table.valueAt(), it returns null.

try{
    System.out.print(table.getValueAt(5,0)); //<- this returns null even if the table.getRowCount() is 6

    for(int i=0; i<table.getRowCount();i++){
        if((Boolean)table.getValueAt(i,1)) val=1;
        else val=0;
        //System.out.print(table.getValueAt(i, 0) +","+ val);
        String sql1 = "INSERT INTO HREmpListofCard (EmpID, CardNbr, Status, Remarks) VALUES ("
            +"'"+empID
            +"','"+table.getValueAt(i, 0).toString()
            +"','"+val
            +"','"+table.getValueAt(i,2).toString()+"')";

        try {
            DBConnect.getConnection().createStatement().executeUpdate(sql1);
        } catch (ClassNotFoundException ex) {
            Logger.getLogger(ListOfCardID.class.getName()).log(Level.SEVERE, null, ex);
        } catch (SQLException ex) {
            Logger.getLogger(ListOfCardID.class.getName()).log(Level.SEVERE, null, ex);
        }
    }
}catch(Exception e){
    System.out.print("\nerror!");
}

推荐答案

关于第二个问题.您可以先在表中检查变量，然后再将其放入查询中.例如，您可以执行以下操作:

As for your second question.You can check your variable in your table before you put it inside your query. For example you can do this:

 String item1;

 if(table.getValueAt(i, 0) != null)
     item1 = table.getValueAt(i, 0);
 else
     item1 = null;

用"table.getValueAt(i，0)"替换item1并为"table.getValueAt(i，2)"创建一个item2

Replace item1 with you "table.getValueAt(i, 0)" and create an item2 for your "table.getValueAt(i,2)"

String sql1 = "INSERT INTO HREmpListofCard (EmpID, CardNbr, Status, Remarks) VALUES ("
        +"'"+empID
        +"','"+ITEM1
        +"','"+val
        +"','"+ITEM2+"')";

我还没有测试过，所以不确定它是否可以工作:)

I haven't tested this, so I'm not sure if it will work :)

祝你好运！

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