问题描述
对于Double/Float，当从十进制转换为二进制表示形式时，会存在一些舍入误差和精度损失.例如，将float设置为"6.1"，然后再次打印出来，则可能会得到报告值，例如"6.099999904632568359375".这是检查2个Double对象是否相等的更好选择:使用BigDecimal或者(Math.abs(double1-double2)< epsilon)
For Double/Float, there are some rounding errors and loss of precision when converting from decimal to binary representation.For example, setting float to "6.1" and then printing it out again, you may get a reported value of something like "6.099999904632568359375".Which is the better option for checking equality of 2 Double objects :Using BigDecimalor(Math.abs(double1 - double2) < epsilon)
推荐答案
这取决于您的用例.如果您使用货币，请使用BigDecimal.否则，如果您可以接受近似值，请使用 Math.abs(double1-double2)<epsilon
It depends on your usecase. If you work with currency, go for BigDecimal.Otherwise if you can live with approximations use Math.abs(double1 - double2) < epsilon
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