问题描述
在我的程序中,表面上有一个圆和一个矩形.我想知道圆和矩形是否相互接触.它必须非常准确.对不起,我没有解释它的细节,但我希望你能理解.
There is a circle and a rect moving on the surface in my program. I want to know if a circle and a rect is touched to each other. It had to be very accurate. I'm sorry for not explaining its detail, but I hope you understood.
推荐答案
考虑到轴对齐的矩形由左上角的原点以及宽度和高度给出:
Consider a axis aligned rectangle is given by a top left origin and a width and a height:
rect_tl = (x, y)
rect_size = (width, height)
一个圆是由一个中心点和一个半径给出的:
And a circle is given by a center point and a radius:
circle_cpt = (x, y)
circle_rad = r
如果要测试这两个形状是否重叠,则需要运行2个测试以捕获所有可能的情况.
If you want to test whether these two shapes overlap, you need to run 2 tests to capture all possible cases.
首先必须测试圆的中心点是否在矩形内.这可以通过 pygame.Rect.collidepoint
:
First it has to be tested if the center point of the circle is inside the rectangle. This can be done by pygame.Rect.collidepoint
with ease:
rect = pygame.Rect(*rect_tl, *rect_size)
isIsect = rect.collidepoint(*circle_cpt)
此外,如果 any
矩形的角点位于圆内.如果圆的角点和圆心之间的距离小于或等于圆的半径,则为这种情况.可以通过 pygame.math.Vector2来表示一个点
,两点之间的距离可以通过 pygame.math.Vector2.distance_to()
:
Furthermore it has to be tested if any
corner point of the rectangle is inside the circle. This is the case if the distance between a corner point and the center point of the circle is less than is or equal the radius of the circle. A point can be represented by pygame.math.Vector2
and the distance between 2 points can be get by pygame.math.Vector2.distance_to()
:
centerPt = pygame.math.Vector2(*circle_cpt)
cornerPts = [rect.bottomleft, rect.bottomright, rect.topleft, rect.topright]
isIsect = any([p for p in cornerPts if pygame.math.Vector2(*p).distance_to(centerPt) <= circle_rad])
结合了两个测试的函数可能看起来像这样:
A function which combines both tests may look like this:
def isectRectCircle(rect_tl, rect_size, circle_cpt, circle_rad):
rect = pygame.Rect(*rect_tl, *rect_size)
if rect.collidepoint(*circle_cpt):
return True
centerPt = pygame.math.Vector2(*circle_cpt)
cornerPts = [rect.bottomleft, rect.bottomright, rect.topleft, rect.topright]
if [p for p in cornerPts if pygame.math.Vector2(*p).distance_to(centerPt) <= circle_rad]:
return True
return False
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