关于pygame.sprite.groupcollide的使用方法

问题描述

看这段代码(她可能有点长):

Look at this code (She may be a little long)：

#Begin
import pygame
from pygame.locals import *

global x, y, picPath
x, y, picPath = 100, 100, 'C:\\Pic\\'

class Ball(pygame.sprite.Sprite):
    def __init__(self):
        pygame.sprite.Sprite.__init__(self)
        self.image = pygame.image.load(picPath + 'boll.png')
        self.image.set_colorkey(0xffffff, 0)
        self.rect = self.image.get_rect()
    def update(self, pos):
        screen.blit(self.image, pos)

class Stone(pygame.sprite.Sprite):
    def __init__(self):
        pygame.sprite.Sprite.__init__(self)
        self.image = pygame.image.load(picPath + 'stone.jpg')
        self.rect = self.image.get_rect()
        self.num = 0
        self.up = 5
    def update(self):
        if(self.up != 370)and(self.num == 0):
            self.up += 5
        elif(self.up == 0)and(self.num == 1):
            self.up += 5
            self.num = 0
        else:
            self.up -= 5
            self.num = 1
        screen.blit(self.image, (305, self.up))

class GameStart:
    def __init__(self):
        self.life = 405
        self.bg = pygame.image.load(picPath + 'bg.jpg')
        self.lf = pygame.image.load(picPath + 'life.jpg')
        player1 = pygame.sprite.Group()
        player2 = pygame.sprite.Group()
        self.cB = Ball()
        self.cS = Stone()
        player1.add(self.cB)
        player2.add(self.cS)
        self.collide = pygame.sprite.groupcollide(player1, player2, 1, 0)
    def update(self):
        if self.collide:
            print 'Yoshi!'
        screen.blit(self.bg, (0, 0))
        self.cB.update((x, y))
        self.cS.update()
        screen.blit(self.lf, (150, self.life))

    def start(self):
        # This is Start!
        print 'Hello'

pygame.init()
screen = pygame.display.set_mode([700,460])
clock = pygame.time.Clock()

game = GameStart()
game.start()

while True:
    clock.tick(50)

    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()

    pygame.display.update()
    game.update()

    kname = pygame.key.get_pressed()
    if kname[pygame.K_LEFT]:
        if x > 0: x = x - 5
    elif kname[pygame.K_RIGHT]:
        if x < 700: x = x + 5
    elif kname[pygame.K_UP]:
        if y > 0: y = y - 5
    elif kname[pygame.K_DOWN]:
        if y < 460: y = y + 5
#End

为什么她一直印着Yoshi"?我只想打印一次，球和石头的碰撞.(我的英文很差)

Why does she keeps printing 'Yoshi'? I just want to print it once, the collision of the Ball and Stone. (My English is poor)

推荐答案

groupcollide 只运行一次.尝试将 groupcollide 移动到 update

groupcollide is only running once. Try moving groupcollide into update

class GameStart:
    def __init__(self):
        self.life = 405
        self.bg = pygame.image.load(picPath + 'bg.jpg')
        self.lf = pygame.image.load(picPath + 'life.jpg')
        self.player1 = pygame.sprite.Group()
        self.player2 = pygame.sprite.Group()
        self.cB = Ball()
        self.cS = Stone()
        self.player1.add(self.cB)
        self.player2.add(self.cS)
    def update(self):
        if pygame.sprite.groupcollide(self.player1, self.player2, 1, 0):
            print 'Yoshi!'
        screen.blit(self.bg, (0, 0))
        self.cB.update((x, y))
        self.cS.update()
        screen.blit(self.lf, (150, self.life))

此外，游戏逻辑在显示已经绘制后更新.除非您出于某种原因想要这种行为，否则您可以在主循环的最后调用 pygame.display.update.

Also, the game logic is updating after the display is already drawn. Unless you want that behavior for some reason, you can call pygame.display.update last in the main loop.

game.update()

kname = pygame.key.get_pressed()
if kname[pygame.K_LEFT]:
    if x > 0: x = x - 5
elif kname[pygame.K_RIGHT]:
    if x < 700: x = x + 5
elif kname[pygame.K_UP]:
    if y > 0: y = y - 5
elif kname[pygame.K_DOWN]:
    if y < 460: y = y + 5

pygame.display.update()

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