本文介绍了在 php 中将单词转换为数字 II的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这里有一个很棒的功能在 PHP 中将单词转换为数字来自埃尔约博.但是我遇到了字符串必须以书面数字开头的问题.如何转换例如iPhone 有二十三万,七百八十三款应用"?
There is a great function here Converting words to numbers in PHP from El Yobo.But I have the problem that the string must begin with a written number.How can convert e.g. "iPhone has two hundred and thirty thousand, seven hundred and eighty-three apps" ?
解释函数:
function wordsToNumber($data) {
// Replace all number words with an equivalent numeric value
$data = strtr(
$data,
array(
'zero' => '0',
'a' => '1',
'one' => '1',
'two' => '2',
'three' => '3',
'four' => '4',
'five' => '5',
'six' => '6',
'seven' => '7',
'eight' => '8',
'nine' => '9',
'ten' => '10',
'eleven' => '11',
'twelve' => '12',
'thirteen' => '13',
'fourteen' => '14',
'fifteen' => '15',
'sixteen' => '16',
'seventeen' => '17',
'eighteen' => '18',
'nineteen' => '19',
'twenty' => '20',
'thirty' => '30',
'forty' => '40',
'fourty' => '40', // common misspelling
'fifty' => '50',
'sixty' => '60',
'seventy' => '70',
'eighty' => '80',
'ninety' => '90',
'hundred' => '100',
'thousand' => '1000',
'million' => '1000000',
'billion' => '1000000000',
'and' => '',
)
);
// Coerce all tokens to numbers
$parts = array_map(
function ($val) {
return floatval($val);
},
preg_split('/[\s-]+/', $data)
);
$stack = new SplStack; // Current work stack
$sum = 0; // Running total
$last = null;
foreach ($parts as $part) {
if (!$stack->isEmpty()) {
// We're part way through a phrase
if ($stack->top() > $part) {
// Decreasing step, e.g. from hundreds to ones
if ($last >= 1000) {
// If we drop from more than 1000 then we've finished the phrase
$sum += $stack->pop();
// This is the first element of a new phrase
$stack->push($part);
} else {
// Drop down from less than 1000, just addition
// e.g. "seventy one" -> "70 1" -> "70 + 1"
$stack->push($stack->pop() + $part);
}
} else {
// Increasing step, e.g ones to hundreds
$stack->push($stack->pop() * $part);
}
} else {
// This is the first element of a new phrase
$stack->push($part);
}
// Store the last processed part
$last = $part;
}
return $sum + $stack->pop();
}
推荐答案
好吧..我不得不承认..这对我个人来说很有趣!!!无论如何......这是代码......你可以在这里测试它:http://www.eyerollweb.com/str2digits/
Well .. i have to admit.. this was interesting to me on a personal level !!! anyway ... here is the code... you can test it here : http://www.eyerollweb.com/str2digits/
这里是代码本身:
<?php
//The Test string
$str = "two hundred thousand six hundred and two";
$numbers = array(
'zero' => 0,
'one' => 1,
'two' => 2,
'three' => 3,
'four' => 4,
'five' => 5,
'six' => 6,
'seven' => 7,
'eight' => 8,
'nine' => 9,
'ten' => 10,
'eleven' => 11,
'twelve' => 12,
'thirteen' => 13,
'fourteen' => 14,
'fifteen' => 15,
'sixteen' => 16,
'seventeen' => 17,
'eighteen' => 18,
'nineteen' => 19,
'twenty' => 20,
'thirty' => 30,
'forty' => 40,
'fourty' => 40, // common misspelling
'fifty' => 50,
'sixty' => 60,
'seventy' => 70,
'eighty' => 80,
'ninety' => 90,
'hundred' => 100,
'thousand' => 1000,
'million' => 1000000,
'billion' => 1000000000);
//first we remove all unwanted characters... and keep the text
$str = preg_replace("/[^a-zA-Z]+/", " ", $str);
//now we explode them word by word... and loop through them
$words = explode(" ", $str);
//i devide each thousands in groups then add them at the end
//For example 2,640,234 "two million six hundred and fourty thousand two hundred and thirty four"
//is defined into 2,000,000 + 640,000 + 234
//the $total will be the variable were we will add up to
$total = 1;
//flag to force the next operation to be an addition
$force_addition = false;
//hold the last digit we added/multiplied
$last_digit = null;
//the final_sum will be the array that will hold every portion "2000000,640000,234" which we will sum at the end to get the result
$final_sum = array();
foreach ($words as $word) {
//if its not an and or a valid digit we skip this turn
if (!isset($numbers[$word]) && $word != "and") {
continue;
}
//all small letter to ease the comparaison
$word = strtolower($word);
//if it's an and .. and this is the first digit in the group we set the total = 0
//and force the next operation to be an addition
if ($word == "and") {
if ($last_digit === null) {
$total = 0;
}
$force_addition = true;
} else {
//if its a digit and the force addition flag is on we sum
if ($force_addition) {
$total += $numbers[$word];
$force_addition = false;
} else {
//if the last digit is bigger than the current digit we sum else we multiply
//example twenty one => 20+1, twenty hundred 20 * 100
if ($last_digit !== null && $last_digit > $numbers[$word]) {
$total += $numbers[$word];
} else {
$total *= $numbers[$word];
}
}
$last_digit = $numbers[$word];
//finally we distinguish a group by the word thousand, million, billion >= 1000 !
//we add the current total to the $final_sum array clear it and clear all other flags...
if ($numbers[$word] >= 1000) {
$final_sum[] = $total;
$last_digit = null;
$force_addition = false;
$total = 1;
}
}
}
// there is your final answer !
$final_sum[] = $total;
print "Final Answer: " . array_sum($final_sum) . "\n";
?>
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