问题描述
如何在字符串中搜索换行符？下面的两个似乎都返回-1 ....！
How do i search a string for a newline character? Both of the below seem to be returning -1....!
theJ = line.IndexOf(Environment.NewLine);
OR
theJ = line.IndexOf('\n');
正在搜索的字符串为 yo\n
我正在解析的字符串包含此 printf（ yo\n）;
我在比较中看到的字符串是这样的： \tprintf（\ yo\n\）;
The string it's searching is "yo\n"the string i'm parsing contains this "printf("yo\n");"the string i see contained during the comparison is this: "\tprintf(\"yo\n\");"
推荐答案
"yo\n" // output as "yo" + newline
"yo\n".IndexOf('\n') // returns 2
"yo\\n" // output as "yo\n"
"yo\\n".IndexOf('\n') // returns -1
确定要搜索 yo\n 而不是 yo ？
根据您的更新，我可以看到我猜对了。如果您的字符串说：
Based on your update, I can see that I guessed correctly. If your string says:
printf("yo\n");
...，则其中不包含换行符。如果确实如此，它将看起来像这样：
... then this does not contain a newline character. If it did, it would look like this:
printf("yo
");
实际上它是一个转义的换行符，或者换句话说，一个反斜杠字符后跟一个'n'。因此，您在调试时看到的字符串是 \tprintf（\ yo\\n\）; 。如果要查找此字符组合，则可以使用：
What it actually has is an escaped newline character, or in other words, a backslash character followed by an 'n'. That's why the string you're seeing when you debug is "\tprintf(\"yo\\n\");". If you want to find this character combination, you can use:
line.IndexOf("\\n")
例如：
"\tprintf(\"yo\\n\");" // output as " printf("yo\n");"
"\tprintf(\"yo\\n\");".IndexOf("\\n") // returns 11
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