从以编程方式创建的tableViewCell中删除图像

问题描述

我想移动一个包含在单元格中的imageView，它可以工作，但是在新位置创建一个新图像，同时保留旧图像（然后显示两个）。我该如何删除旧的？使用的代码：

I would like to move an imageView contained on a cell and it works but creating a new image at new position keeping old image (then two are shown). How could I remove old one?? used code:

UIImage *cellImage = [UIImage imageNamed:(@"%@", showIconName)];
UIImageView *imageViewToPutInCell = [[UIImageView alloc] initWithImage:cellImage];

imageViewToPutInCell.frame = CGRectMake(iconPos, 7, cellImage.size.width, cellImage.size.height);
[cell.contentView addSubview:imageViewToPutInCell];

每次重新加载tableView时，它都会创建一个新的重叠图像。

every time that I reload tableView, it creates a new overlapped image.

[cell.contentView removeFromSuperview];

[cell.contentView removeFromSuperview]; used before, removes it but then new image is not created.

推荐答案

有两种方法可以执行此操作。如果没有子类，则可以在imageViewToPutInCell上设置标签，然后再使用-[UIView viewWithTag：]查找并删除视图：

There are a couple of ways to do this. Without subclassing, you could set the tag on your imageViewToPutInCell, then later on, use -[UIView viewWithTag:] to find and remove the view:

int            imageViewTag = 1234;

[[cell.contentView viewWithTag: imageViewTag] removeFromSuperview];
imageViewToPutInCell.tag = imageViewTag;
...

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