问题描述
以下代码显示了两个面板，黄色和蓝色，其中蓝色是黄色的孩子.
The following code show two panels, yellow and blue, where blue is a child of yellow.
如果我点击蓝色面板的中心，两个面板都会处理鼠标事件.
If I click into the center of blue panel, mouse event is handled with both panels.
如何以编程方式模拟相同的行为?
How to simulate the same behavior programmatically?
在 Fire event 按钮中，我尝试这样做，但失败了:生成的事件似乎只能由黄色窗格处理.
In the Fire event button I tried to do this, but failed: generated event appeared to handled only by yellow pane.
是否可以发布事件，以便所有孩子都像处理本机"事件一样处理它?
Is it possible to post event so that it processed by all children as if it happen with "native" events?
import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.Event;
import javafx.event.EventHandler;
import javafx.geometry.Insets;
import javafx.geometry.Point2D;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.input.MouseButton;
import javafx.scene.input.MouseEvent;
import javafx.scene.layout.*;
import javafx.scene.paint.Color;
import javafx.stage.Stage;
public class FireMouseEventProgrammatically extends Application {
@Override
public void start(Stage primaryStage) throws Exception {
BorderPane root = new BorderPane();
AnchorPane yellowPane = new AnchorPane();
yellowPane.setBackground(new Background(new BackgroundFill(Color.YELLOW, CornerRadii.EMPTY, Insets.EMPTY)));
yellowPane.setOnMouseClicked(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
System.out.print("yellowPane clicked ");
printMouseEvent(event);
System.out.println("");
}
});
root.setCenter(yellowPane);
Pane bluePane = new Pane();
bluePane.setBackground(new Background(new BackgroundFill(Color.BLUE, CornerRadii.EMPTY, Insets.EMPTY)));
bluePane.setOnMouseClicked(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
System.out.print("bluePane clicked ");
printMouseEvent(event);
System.out.println("");
}
});
AnchorPane.setLeftAnchor(bluePane, 200.);
AnchorPane.setRightAnchor(bluePane, 200.);
AnchorPane.setTopAnchor(bluePane, 200.);
AnchorPane.setBottomAnchor(bluePane, 200.);
yellowPane.getChildren().add(bluePane);
FlowPane buttonPane = new FlowPane();
buttonPane.setHgap(5);
buttonPane.setPadding(new Insets(5, 5, 5, 5));
root.setBottom(buttonPane);
Button fireEventButton = new Button();
fireEventButton.setText("Fire event");
fireEventButton.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
double blueX = bluePane.getWidth()/2;
double blueY = bluePane.getHeight()/2;
Point2D screenCoords = bluePane.localToScreen(blueX, blueY);
Point2D sceneCoords = bluePane.localToScene(blueX, blueY);
Event.fireEvent(yellowPane, new MouseEvent(MouseEvent.MOUSE_CLICKED,
sceneCoords.getX(), sceneCoords.getY(), screenCoords.getX(), screenCoords.getY(), MouseButton.PRIMARY, 1,
true, true, true, true, true, true, true, true, true, true, null));
}
});
buttonPane.getChildren().add(fireEventButton);
Scene scene = new Scene(root, 800, 600);
primaryStage.setScene(scene);
primaryStage.show();
}
private void printMouseEvent(MouseEvent event) {
System.out.print(String.format("x = %f, y = %f, xScreen = %f, yScreen = %f", event.getX(), event.getY(), event.getScreenX(), event.getScreenY()));
}
public static void main(String[] args) {
FireMouseEventProgrammatically.launch(args);
}
}
更新
我不能明确提及子节点，因为在一般情况下，它可以是多个子节点.
I can't mention child node explicitly, because in general case it can be numerous number of children.
我怎么知道要定位哪一个?
How would I know which one to target?
我想传递坐标，让系统自动确定目标.
I would like to pass coordinates and let system determine targets automatically.
推荐答案
实际(物理)点击和程序化点击之间的区别在于，在第一种情况下，原始事件目标是 bluePane(因为它在视觉上是最上面的"Node)，在后一种情况下，目标是 yellowPane.
The difference between the actual (phisycal) clicking and your programmatic clicking is, that in the first case the original event target is bluePane (as it is the "uppermost" Node visually), in the latter case the target is yellowPane.
所以，当路由构建发生时(请参考事件传递流程部分) 在第一种情况下，路由将是 root -> yellowPane -> bluePane，在第二种情况下它将是只有 root -> yellowPane，因此 bluePane 不受事件影响.
So, when the route construction occurs (please refer to the Event Delivery Process section) in the first case the route will be root -> yellowPane -> bluePane, and in the second case it will be only root -> yellowPane, hence the bluePane is untouched by the event.
基于此，您可以定位bluePane:
Event.fireEvent(bluePane, new MouseEvent(MouseEvent.MOUSE_CLICKED,
sceneCoords.getX(), sceneCoords.getY(), screenCoords.getX(), screenCoords.getY(), MouseButton.PRIMARY, 1,
true, true, true, true, true, true, true, true, true, true, null));
或者您可以使用 Robot 例如来生成点击:
Or you can use a Robot for example to generate the click:
try {
robot = new java.awt.Robot();
robot.mouseMove((int)screenCoords.getX(), (int)screenCoords.getY());
robot.mousePress(16);
robot.mouseRelease(16);
robot.mouseMove((int) originalLocation.getX(), (int)originalLocation.getY());
} catch (AWTException e) {
e.printStackTrace();
}
更新 1:
如果您想坚持使用 JavaFX 方式，现在的问题是如何确定位置上的最上层"Node.
If you want to stick with the JavaFX way, the question is now how to determine the "uppermost" Node on a position.
这是不可能以干净的方式进行的一件事.已经有一个关于此的功能请求.
This is one thing that is not possible in a clean way. There is already a feature request about this.
我在 fxexperience 的辅助方法上发现了这个用于确定某个位置的Node:
I have found this on helper method on fxexperience that can be used to determinte the Node on a certain position:
public static Node pick(Node node, double sceneX, double sceneY) {
Point2D p = node.sceneToLocal(sceneX, sceneY, true /* rootScene */);
// check if the given node has the point inside it, or else we drop out
if (!node.contains(p)) return null;
// at this point we know that _at least_ the given node is a valid
// answer to the given point, so we will return that if we don't find
// a better child option
if (node instanceof Parent) {
// we iterate through all children in reverse order, and stop when we find a match.
// We do this as we know the elements at the end of the list have a higher
// z-order, and are therefore the better match, compared to children that
// might also intersect (but that would be underneath the element).
Node bestMatchingChild = null;
List<Node> children = ((Parent)node).getChildrenUnmodifiable();
for (int i = children.size() - 1; i >= 0; i--) {
Node child = children.get(i);
p = child.sceneToLocal(sceneX, sceneY, true /* rootScene */);
if (child.isVisible() && !child.isMouseTransparent() && child.contains(p)) {
bestMatchingChild = child;
break;
}
}
if (bestMatchingChild != null) {
return pick(bestMatchingChild, sceneX, sceneY);
}
}
return node;
}
你可以像这样使用:
Node pick = pick(root, sceneCoords.getX(), sceneCoords.getY());
Event.fireEvent(pick, new MouseEvent(MouseEvent.MOUSE_CLICKED,
sceneCoords.getX(), sceneCoords.getY(), screenCoords.getX(), screenCoords.getY(), MouseButton.PRIMARY, 1,
true, true, true, true, true, true, true, true, true, true, null));
更新 2:
您也可以使用已弃用的方法 Node.impl_pickNode(PickRay pickRay, PickResultChooser result) 在场景位置上获取相交的Node:
You can also use the deprecated method Node.impl_pickNode(PickRay pickRay, PickResultChooser result) to get the intersected Node on a scene position:
PickRay pickRay = new PickRay((int) sceneCoords.getX(), (int) sceneCoords.getY(), 1.0, 1.0, 1.0);
PickResultChooser pickResultChooser = new PickResultChooser();
root.impl_pickNode(pickRay, pickResultChooser);
Node intersectedNode = pickResultChooser.getIntersectedNode();
您也可以类似地将此Node用作目标.
You can use also this Node as target similarly.
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