问题描述
我想生成一个HTML表并将MySQL表中的记录显示为列而不是行,例如:
I want to generate an HTML table and display records from MySQL tables as columns, not rows, like:
星期名称在表"week"中,并且每个星期的记录还包含该周的会话数:
The week names are in table 'week' and each week record also contains the number of sessions for that week:
+---------+-----------+----------+-----------+
| week_pk | week_name | sessions | cohort_fk |
+---------+-----------+----------+-----------+
| 1 | Week 1 | 3 | 1 |
| 2 | Week 2 | 2 | 1 |
| 3 | Week 3 | 1 | 1 |
+---------+-----------+----------+-----------+
同类群组表是:
+-----------+-------------+-------------+-------------+
| cohort_pk | cohort_name | cohort_code | cohort_year |
+-----------+-------------+-------------+-------------+
| 1 | Some name | MICR8976 | 2014 |
+-----------+-------------+-------------+-------------+
我找到了一些代码,这些代码可以在表中以HTML表格列的形式生成记录,好的(我确定可以改进此代码...).
I found some code which generates records in a table as HTML table columns, OK (I'm sure this code could be improved...).
所以,问题是我如何才能修改此代码以在每周的对话中生成HTML表中的会话列?例如,对于HTML表中的第1周"列,第3个会话列,以及其他周"列,依此类推?
So, the question is how can I modify this code to generate the session columns in the HTML table for each week coloumn? For example, for the Week 1 column in the HTML table, the 3 session columns, and so on for the other week columns?
对寻求解决方案的任何帮助表示赞赏.
Any help towards a solution appreciated.
$query = "SELECT * FROM cohort, week
WHERE week.cohort_fk = cohort.cohort_pk
AND cohort.cohort_year = '$year'
AND cohort.cohort_pk = '$cohort'";
$result = mysql_query($query, $connection) or die(mysql_error());
echo "<table width = 50% border = '1' cellspacing = '2' cellpadding = '0'>";
$position = 1;
while ($row = mysql_fetch_array($result)){
if($position == 1){
echo "<tr>";
}
echo " <td width='50px'>" . $row['week_name'] . "</td> ";
if($position == 3){
echo "</tr> ";
$position = 1;
}else{
$position++;
}
}
$end = "";
if($position != 1){
for($z=(3-$position); $z>0; $z--){
$end .= "<td></td>";
}
$end .= "</tr>";
}
echo $end."</table> ";
在以下示例中使用
推荐答案
mysqli_ *函数.
mysqli_* functions are used in the following example.
$year = 2014; //for the testing purpose
$cohort = 1; //for the testing purpose
$query = "SELECT * FROM cohort, week
WHERE week.cohort_fk = cohort.cohort_pk
AND cohort.cohort_year = '$year'
AND cohort.cohort_pk = '$cohort'";
$dblink = mysqli_connect("localhost", "root", "", "test");
$result = mysqli_query($dblink, $query);
echo "<table border='1'>";
echo "<tr><td>Name</td>";
$second_row = "<tr><td>Session</td>";
while( $row = mysqli_fetch_assoc($result) ){
$weekname = $row["week_name"];
$n_session = $row["sessions"];
echo "<td colspan='$n_session'>$weekname</td>";
for($i=1; $i<=$n_session; $i++){
$second_row .= "<td>S$i</td>";
}
}//end while
echo "</tr>";
echo "$second_row</tr>";
echo "</table>";
已添加:生成第三行-
ADDED:to generate third row -
$year = 2014;
$cohort = 1;
$query = "SELECT * FROM cohort, week
WHERE week.cohort_fk = cohort.cohort_pk
AND cohort.cohort_year = '$year'
AND cohort.cohort_pk = '$cohort'";
$dblink = mysqli_connect("localhost", "root", "", "test");
$result = mysqli_query($dblink, $query);
echo "<table border='1'>";
echo "<tr><td>Name</td>";
$second_row = "<tr><td>Session</td>";
$totalcolumn = 1; //for the third row
while( $row = mysqli_fetch_assoc($result) ){
$weekname = $row["week_name"];
$n_session = $row["sessions"];
$totalcolumn += $n_session; //for the third row
echo "<td colspan='$n_session'>$weekname</td>";
for($i=1; $i<=$n_session; $i++){
$second_row .= "<td>S$i</td>";
}
}//end while
echo "</tr>";
echo $second_row . "</tr>";
echo "<tr>"; //for the third row
for($i=1; $i<=$totalcolumn; $i++){ //for the third row
echo "<td>data-set</td>"; //for the third row
} //for the third row
echo "</tr>"; //for the third row
echo "</table>";
您可以在data-set
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