本文介绍了django admin list_filter“或”;健康)状况的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

很抱歉,如果以前已经回答过这个问题,但是我做了很多谷歌搜索却没有成功。



我知道如何创建自定义的 list_filter 在管理员视图中(例如,将 SimpleFilter 子类化)。



我真正想要的是(在管理列表视图上)检查不同过滤器的一种方法,这些过滤器将它们组合为OR公式。



例如,假设您有:

 #models.py 
class Foo(models.Model):
foobar = ...
foofie = ...
...

#admin.py
类FooAdmin(admin.ModelAdmin):
list_filter =( foobar, foofie)
...

FooAdmin 生成的管理列表视图中,我可以选择按 foobar 或 foofie 。是否可以通过以下公式过滤它们: foobar = X或foofie = Y ,其中 X Y foobar foofie 可以假定的两个值?



有可能吗?



我知道在django管理员视图中并非一切皆有可能,但似乎常见的要求,我想知道我是否错过了理解或阅读的东西。



也欢迎第三方应用允许它。谢谢:)

解决方案

我刚刚找到了第三方应用程序,它是


sorry if this question has been answered before, but I did a lot of googling without success.

I know how to create custom list_filters in admin views (e.g. subclassing SimpleFilter).

What I really would like, is a way (on the admin list view) to "check" different filters that combines them in a OR formula.

As an example, suppose you have:

# models.py
class Foo(models.Model):
    foobar = ...
    foofie = ...
...

# admin.py
class FooAdmin(admin.ModelAdmin):
    list_filter = ( "foobar", "foofie" )
...

In the admin list view generated by FooAdmin I can choose to filter records either by foobar or by foofie. Is there a way to filter them by the formula: foobar = X OR foofie = Y, where X and Y are two values that foobar and foofie can assume?

Is it even possible?

I know not everything is possible in the django admin views, but it seems a very common request, I wonder if I missed to understand or read something.

Also third party apps allowing it are welcome. Thanks :)

解决方案

I found a third party app just now, it is django-advanced-filters which may fit you requirement .

It has:

I have run a test, add a OR field would work.This is the screenshot:

这篇关于django admin list_filter“或”;健康)状况的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-30 23:49