问题描述
很抱歉,如果以前已经回答过这个问题,但是我做了很多谷歌搜索却没有成功。
我知道如何创建自定义的 list_filter
在管理员视图中(例如,将 SimpleFilter
子类化)。
我真正想要的是(在管理列表视图上)检查不同过滤器的一种方法,这些过滤器将它们组合为OR公式。
例如,假设您有:
#models.py
class Foo(models.Model):
foobar = ...
foofie = ...
...
#admin.py
类FooAdmin(admin.ModelAdmin):
list_filter =( foobar, foofie)
...
在 FooAdmin
生成的管理列表视图中,我可以选择按 foobar
或 foofie
。是否可以通过以下公式过滤它们: foobar = X或foofie = Y
,其中 X
和 Y
是 foobar
和 foofie
可以假定的两个值?
有可能吗?
我知道在django管理员视图中并非一切皆有可能,但似乎常见的要求,我想知道我是否错过了理解或阅读的东西。
也欢迎第三方应用允许它。谢谢:)
我刚刚找到了第三方应用程序,它是
sorry if this question has been answered before, but I did a lot of googling without success.
I know how to create custom list_filter
s in admin views (e.g. subclassing SimpleFilter
).
What I really would like, is a way (on the admin list view) to "check" different filters that combines them in a OR formula.
As an example, suppose you have:
# models.py
class Foo(models.Model):
foobar = ...
foofie = ...
...
# admin.py
class FooAdmin(admin.ModelAdmin):
list_filter = ( "foobar", "foofie" )
...
In the admin list view generated by FooAdmin
I can choose to filter records either by foobar
or by foofie
. Is there a way to filter them by the formula: foobar = X OR foofie = Y
, where X
and Y
are two values that foobar
and foofie
can assume?
Is it even possible?
I know not everything is possible in the django admin views, but it seems a very common request, I wonder if I missed to understand or read something.
Also third party apps allowing it are welcome. Thanks :)
I found a third party app just now, it is django-advanced-filters which may fit you requirement .
It has:
I have run a test, add a OR field
would work.This is the screenshot:
这篇关于django admin list_filter“或”;健康)状况的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!