问题描述
页面 url 类似于 /people?search=name当我使用水豚的 current_path 方法时，它只返回 /people.
The page url is something like /people?search=namewhile I used current_path method of capybara it returned /people only.
current_path.should == people_path(:search => 'name')
但它没有说
expected: "/people?search=name"
got: "/people"
我们怎样才能让它通过?有没有办法做到这一点?
How we can make it pass? Is there is any way to do this?
推荐答案
我已更新此答案以反映水豚的现代惯例.我认为这是理想的，因为这是公认的答案，也是许多人在寻找解决方案时所参考的答案.话虽如此，检查当前路径的正确方法是使用 Capybara 提供的 has_current_path? 匹配器，如下所述:点击这里
I've updated this answer to reflect modern conventions in capybara. I think this is ideal since this is the accepted answer, and what many people are being referred to when looking for a solution. With that said, the correct way to check the current path is to use the has_current_path? matcher provided by Capybara, as documented here: Click Here
示例用法:
expect(page).to have_current_path(people_path(search: 'name'))
正如您在文档中所见，还有其他选项可用.如果当前页面是 /people?search=name 但你只关心它在 /people 页面上而不考虑参数，你可以发送 only_path 选项:
As you can see in the documentation, other options are available. If the current page is /people?search=name but you only care that it's on the /people page regardless of the param, you can send the only_path option:
expect(page).to have_current_path(people_path, only_path: true)
另外，如果你想比较整个 URL:
Additionally, if you want to compare the entire URL:
expect(page).to have_current_path(people_url, url: true)
感谢 Tom Walpole 指出这种方法.
Credit to Tom Walpole for pointing out this method.
这篇关于如何使用 Capybara 获取带有查询字符串的当前路径的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！