使用POST数据打开Window.open()并使用PHP获取数据

问题描述

我有带有用户名和密码的表格.当我单击提交"按钮时，用户名和密码将传递到另一页并打开新窗口.

I have form with username and password. when i click on submit buttom then username and password will pass to another page and open new window.

我知道我将像GET请求一样传递此数据

i know that i will pass this data by GET request like

window.open('url.php?unm=username&pass=password','_blank');

但就我而言，我不想在url中显示数据.我想使用POST方法在url.php页面中获取数据.

but in my case i don't want to display data in url. I want to use POST Method To get data in url.php page.

那么如何做到这一点.请帮助..谢谢您提前

So How to do this. Please Help.. Thanks For Advance

以下我使用的代码:

$.post("url.php?unm=username&pass=password",function(data){
    $("#form").hide();
});

推荐答案

您需要处理表单提交，然后打开新窗口

You need to do with form submit and then open new window

<form id="Form" method="post" action="url.php" target="TheWindow">
<input type="hidden" name="unm" value="" />
<input type="hidden" name="pass" value="" />
</form>
<script>
function Post(name,password) {
  var f = document.getElementById('Form');
  f.unm.value = name;
  f.pass.value = password;
  window.open('', 'TheWindow');
  f.submit();
}
Post("username","password");
</script>

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