基本的python IO，请理解文件目录的使用方法。

问题描述

这有效：

fpath = 'D:\\OSGM\\Data\\'
fname_in = 'OGSM_filtJul13.csv'
full_name_in = fpath + fname_in
dataframe = pd.read_csv(full_name_in)

但这不是：

Dat = pd.read_csv('D:\\OGSM\\Data\\OGSM_filtJul13.csv')

并返回：
FileNotFoundError：文件b'D：\ tOSM \ data \OGSM_filtJul13.csv'不存在

And returns:FileNotFoundError: File b'D:\OGSM\Data\OGSM_filtJul13.csv' does not exist

显然这些是我对IO缺少的文件/目录语法。

Clearly these is something I am missing about IO file/directory syntax.

有什么建议吗？
P

Any advice?P

推荐答案

所以问题似乎是你的字符串被强制转换为bytestring。我重新创建了你的问题：

So the problem seems that your string is coerced to bytestring. I recreated your problem:

首先，使用bytestring

First, with a bytestring

> pd.read_csv(b'test.csv')
Traceback (most recent call last):
  File "python", line 1, in <module>
  File "pandas/_libs/parsers.pyx", line 384, in pandas._libs.parsers.TextReader.__cinit__
  File "pandas/_libs/parsers.pyx", line 713, in pandas._libs.parsers.TextReader._setup_parser_source
OSError: Expected file path name or file-like object, got <class 'bytes'> type

鉴于：

>  pd.read_csv('test.csv')
output:
=> Empty DataFrame
Columns: [foo;bar]
Index: []

>  pd.read_csv(u'test.csv')
=> Empty DataFrame
Columns: [foo;bar]
Index: []

为了避免这种问题，特别是在windows 中，
尝试使用正确的os.path方法来连接路径：

To avoid this kind of problems, especially in windows,Try using proper os.path methods to join paths :

import os

fpath = os.path.join("D:", os.sep, "OSGM", "Data")
fname_in = 'OGSM_filtJul13.csv'
full_name_in = os.path.join(fpath,fname_in)
dataframe = pd.read_csv(full_name_in)

注意：在python2中，问题似乎不会发生。

N.B: In python2, the problem doesn't seem to occur.

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