问题描述
我需要使用HttpClient来做一个POST json字符串。以下将是我的代码。从另一端,Json被映射到一个对象。
I need to do a POST json string , using HttpClient. Following will be the code i have. From the other end the Json is mapped to an object.
HttpClient client = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(url);
String jsonData = "{ \"provider\" : null , \"password\" : \"a\", \"userid\" : \"mlpdemo\\mlpdemoins\" }";
post.setEntity(new ByteArrayEntity( jsonData.toString().getBytes("UTF8")));
HttpResponse response = client.execute(post);
这里所有其他人都正确映射期望userId。这里的问题是反斜杠( mlpdemo \ mlpdemins )。我猜。如果我发送一个字符串作为用户ID,它将被映射而没有任何问题。
例如: -
Here all others are correctly mapping expect the userId. Here the problem is with the backward slash(mlpdemo\mlpdemins). I guess. If I send a single string as the user id it will be mapped without any issues.Eg:-
String jsonData = "{ \"provider\" : null , \"password\" : \"a\", \"userid\" : \"mlpdemoins\" }";
这样做。
但我需要这个( mlpdemo \ mlpdemins )将通过POSt发送。请帮帮我。
But I need this (mlpdemo\mlpdemins)to be sent through the POSt. Please help me out.
String jsonData = "{ \"provider\" : null , \"password\" : \"a\", \"userid\" : \"mlpdemo\\mlpdemoins\" }";
以下是我得到的例外情况。
Here is the exception Im getting.
com.fasterxml.jackson.core.JsonParseException: Unrecognized character escape 'm' (code 109)
at [Source: java.io.InputStreamReader@29f0a0a2; line: 1, column: 62]
BadRequestException (0ea35150-f33a-4932-a31e-8a1048af53ad): 400 Bad Request, com.strategicgains.restexpress.serialization.DeserializationException: com.fasterxml.jackson.core.JsonParseException: Unrecognized character escape 'm' (code 109)
at [Source: java.io.InputStreamReader@29f0a0a2; line: 1, column: 62]
at com.strategicgains.restexpress.Request.getBodyAs(Request.java:165)
at com.strategicgains.restexpress.Request.getBodyAs(Request.java:181)
推荐答案
mlpdemo \ mlpdemoins
是一个无效的字符串,你不能在JSON中使用它。但你可以轻松地使用 mlpdemo \\mlpdemoins
。
mlpdemo\mlpdemoins
is an invalid string you can't use it in JSON . But you can use mlpdemo\\mlpdemoins
easily.
以下代码对我来说没问题:
below code works fine for me :
String jsonData = "{ \"provider\" : null , \"password\" : \"a\", \"userid\" : \"mlpdemo\\\\mlpdemoins\" }";
ObjectMapper mapper=new ObjectMapper();
System.out.println(mapper.readTree(jsonData));
它将产生此输出JSON:
It will produce this output JSON :
{"provider":null,"password":"a","userid":"mlpdemo\\mlpdemoins"}
这篇关于Java + jackson解析错误无法识别的字符转义的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!