问题描述
这是什么意思，我有一个用c ++编写的函数，要将资金存入帐户。该函数应该能够接受浮点数，双精度数，整数等，因为这些都是输入的有效形式，因为我所需要的只是一个要存入的数字。
What I mean is this, I have a function in c++ where I want to deposit money into an account. This function should be able to accept floats, doubles, integers, etc. as these are all valid forms of an input, as all I need is a number to deposit.
因此，我声明：
template <typename type>
void Deposit(type t) {...}
现在我唯一的问题就是这样：理论上，此类的用户可能会将char或string传递给此函数，并且这样做会产生意想不到的后果。我将如何限制类型为整数，浮点数，双精度数和短裤？是否可以将其限制在函数定义之内，以便其他人在使用此函数编程时遇到编译器/链接器错误，而不必使用 try {...} catch（...）{。 ..} ？
Now the only issue I have is this: theoretically, a user of this class down the road could pass a char or string to this function and have unintended consequences of doing so. How would I go about restricting type to integers, floats, doubles and shorts? Is it possible to restrict this within the function definition so that others, when programming with this function get a compiler/linker error rather than having to use try{...} catch(...){...}?
推荐答案
您需要的内容将模板类型限制为算术类型（整数或浮点数）。您可以像这样使用它
What you need std::is_arithmetic to constrain the template type to a arithmetic types (integral or floating point). You can use it like
template <typename T, typename std::enable_if<std::is_arithmetic<T>::value>::type* = nullptr>
void Deposit(T t) {...}
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