片段取代（）不是更换所有片段

问题描述

如果我调用add（）的片段A和B具有相同viewId，然后尝试调用替换（）与C片段的viewId，只有一个片段是越来越拆下，用碎片B和C.根据碰得该文档，A和B都应该用C来代替......还是我阅读文档错了？

下面是一个组合，做这样的：

 公共类FragmentActivity扩展SherlockFragmentActivity {
    @覆盖
    公共无效的onCreate（最终捆绑savedInstanceState）{
        super.onCreate（savedInstanceState）;        的setContentView（R.layout.main）;        。。getSupportFragmentManager（）调用BeginTransaction（）加（R.id.fragment，新碎裂（））加（R.id.fragment，新FragmentB（））提交（）;        （（按钮）findViewById（R.id.swap））setOnClickListener。（新View.OnClickListener（）{
            @覆盖
            公共无效的onClick（最终查看视图）{
                。getSupportFragmentManager（）调用BeginTransaction（）取代（R.id.fragment，新FragmentC（））提交（）;
            }
        }）;
    }
}
 

解决方案

综观文档，.replace调用需要一个片段作为一个参数的方法。所以我猜想，这只是为了更换一个片段。我真的不明白，你为什么会在第一时间添加两个片段相同的ID。

If I call add() for fragments A and B with the same viewId and then try to call replace() on that viewId with fragment C, only fragment A is getting removed, ending up with fragments B and C. According to the docs, BOTH A and B should be replaced by C...or am I reading the docs wrong?

Here's one combination that does this:

public class FragmentActivity extends SherlockFragmentActivity {
    @Override
    public void onCreate(final Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        setContentView(R.layout.main);

        getSupportFragmentManager().beginTransaction().add(R.id.fragment, new FragmentA()).add(R.id.fragment, new FragmentB()).commit();

        ((Button) findViewById(R.id.swap)).setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(final View view) {
                getSupportFragmentManager().beginTransaction().replace(R.id.fragment, new FragmentC()).commit();
            }
        });
    }
}

解决方案

Looking at the docs, .replace calls a method that takes a fragment as a parameter. So I would guess that it is only meant to replace one fragment. I don't really understand why you would add two fragments to the same id in the first place.

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