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问题描述
我已按照来验证XML文件。但是我在验证XML文件时收到异常。我做错了什么?我的代码:
XML架构:
I have followed this tutorial for validating XML files. But I am receiving exception when validating XML file. What I am doing wrong? My codes:
XML schema:
<?xml version="1.0" encoding="utf-8" ?>
<!-- definition of simple elements -->
<xs:element name="first_name" type="xs:string" />
<xs:element name="last_name" type="xs:string" />
<xs:element name="phone" type="xs:string" />
<!-- definition of attributes -->
<xs:attribute name="type" type="xs:string" use="required"/>
<xs:attribute name="date" type="xs:date" use="required"/>
<!-- definition of complex elements -->
<xs:element name="reporter">
<xs:complexType>
<xs:sequence>
<xs:element ref="first_name" />
<xs:element ref="last_name" />
<xs:element ref="phone" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="report">
<xs:complexType>
<xs:attribute ref="type"/>
<xs:attribute ref="date" />
<xs:sequence>
<xs:element ref="reporter" />
</xs:sequence>
</xs:complexType>
</xs:element>
要验证的XML文件:
<?xml version="1.0" encoding="utf-8" ?>
<report type="5" date="2012-12-14">
<reporter>
<first_name>FirstName</firstname>
<last_name>Lastname</lastname>
<phone>+xxxxxxxxxxxx</phone>
</reporter>
</report>
用于验证的Java源:
Java source for validating:
import javax.xml.XMLConstants;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.*;
import org.xml.sax.SAXException;
import java.io.*;
public class ProtocolValidator
{
public static void main(String [] args) throws Exception
{
Source schemaFile = new StreamSource(new File("schema.xsd"));
Source xmlFile = new StreamSource(new File("test_xml.xml"));
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = schemaFactory.newSchema(schemaFile);
Validator validator = schema.newValidator();
try{
validator.validate(xmlFile);
System.out.println(xmlFile.getSystemId() + " is valid");
}
catch (SAXException e)
{
System.out.println(xmlFile.getSystemId() + " is NOT valid");
System.out.println("Reason: " + e.getLocalizedMessage());
}
}
}
我收到的例外情况:
Exception in thread "main" org.xml.sax.SAXParseException; systemId: file:/root/test/schema.xsd; lineNumber: 4; columnNumber: 50; The prefix "xs" for element "xs:element" is not bound.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198)...
推荐答案
XML模式文件本身需要是有效的XML文档。您缺少 xs
前缀的外部架构元素和名称空间声明。
The XML schema file itself needs to be a valid XML document. You are missing the outer schema element and the namespace declaration for the xs
prefix.
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<!-- schema elements here -->
</xs:schema>
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