查找字符数组长度

查找字符数组长度

本文介绍了查找字符数组长度的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一些code如下:

I have some code as follows

    int i=0;
    char a[7]={0x00,0xdc,0x01,0x04};
    int len=0;
    len = sizeof(a);
    printf("The Length is : %d", len);

在这里,我想找到在C数组的长度?
我该怎么办呢?

Here I want to find the length of the array a in c?How can I do it?

推荐答案

按照惯例C字符串是空值终止。这意味着,有一个在与零值结束一个额外的字节( 0×00 )。那做了一个字符串(如的printf )的任何函数会考虑一个字符串结束时,发现空。这也意味着,如果你的字符串不是空终止,它会继续下去,直到找到一个空字符,它可以产生一些有趣的结果!

By convention C strings are 'null-terminated'. That means that there's an extra byte at the end with the value of zero (0x00). Any function that does something with a string (like printf) will consider a string to end when it finds null. This also means that if your string is not null terminated, it will keep going until it finds a null character, which can produce some interesting results!

由于你的数组中的第一项为0x00,它会被认为是零长度(没有字符)。

As the first item in your array is 0x00, it will be considered to be length zero (no characters).

如果您定义您的字符串是:

If you defined your string to be:

char a[7]={0xdc,0x01,0x04,0x00};

例如。空值终止

那么你可以使用来衡量长度存储在数组中的字符串

then you can use strlen to measure the length of the string stored in the array.

的sizeof 衡量一个类型的大小。这是不是你想要的。还记得在数组中的字符串可能比数组的长度短。

sizeof measures the size of a type. It is not what you want. Also remember that the string in an array may be shorter than the size of the array.

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08-30 06:20