如何排序数字式的字符串数组

如何排序数字式的字符串数组

本文介绍了如何排序数字式的字符串数组?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个文件名数组,我想通过数字式的排序,请给我一个解决方案。

例1:

原始数组: [name99.txt,name98.txt,name100.txt] 结果
排序的数组: [name98.txt,name99.txt,name100.txt] 结果
(使用字符串排序,排序的结果是 [name100.txt,name98.txt,name99.txt]

例2:

原始数组: [a99.txt,b98.txt,b100.txt] 结果
排序的数组: [a99.txt,b98.txt,b100.txt] 结果
(使用字符串排序,排序的结果是 [a99.txt,b100.txt,b99.txt]


解决方案

 的String [] = AR新的字符串[] {name99.txt,name98.txt,name100 。文本 };
的Array.Sort(AR,(A,B)=> int.Parse(Regex.Replace(一,[^ 0-9],)) - int.Parse(Regex.Replace(二,[ ^ 0-9],)));的foreach(AR中的一个变种)
    Console.WriteLine(一);

以上假设您的文件传真名为 ###名。TXT 。对于真正的数字排序,请使用以下更复杂的版本:

 公共静态无效NumericalSort(字符串[] AR)
{
    正则表达式RGX =新的正则表达式(([^ 0-9] *)([0-9] +));
    的Array.Sort(AR,(A,B)=>
    {
        变种MA = rgx.Matches(一);
        VAR MB = rgx.Matches(B);
        的for(int i = 0; I< ma.Count ++ I)
        {
            INT RET = MA [I] .Groups [1] .Value.CompareTo(MB [I] .Groups [1]。价值);
            如果(RET!= 0)
                返回RET;            RET = int.Parse(MA [I] .Groups [2] .value的) - int.Parse(MB [I] .Groups [2]。价值);
            如果(RET!= 0)
                返回RET;
        }        返回0;
    });
}静态无效的主要(字串[] args)
{
    字符串[] = AR新的字符串[] {a99.txt,b98.txt,b100.txt};    NumericalSort(AR);    的foreach(AR中的一个变种)
        Console.WriteLine(一);
}

I have a filenames array, I want to sort it by numeric style, please give to me a solution.

Example1:

Original array: [name99.txt, name98.txt, name100.txt]
Sorted array: [name98.txt, name99.txt, name100.txt]
(Using string sorting, result of sorting is [name100.txt, name98.txt, name99.txt])

Example2:

Original array: [a99.txt, b98.txt, b100.txt]
Sorted array: [a99.txt, b98.txt, b100.txt]
(Using string sorting, result of sorting is [a99.txt, b100.txt, b99.txt])

解决方案
string[] ar = new string[] { "name99.txt", "name98.txt", "name100.txt" };
Array.Sort(ar, (a, b) => int.Parse(Regex.Replace(a, "[^0-9]", "")) - int.Parse(Regex.Replace(b, "[^0-9]", "")));

foreach (var a in ar)
    Console.WriteLine(a);

The above assumed that your files are allways called name###.txt. For the real numeric sorting use the following more complicated version:

public static void NumericalSort(string[] ar)
{
    Regex rgx = new Regex("([^0-9]*)([0-9]+)");
    Array.Sort(ar, (a, b) =>
    {
        var ma = rgx.Matches(a);
        var mb = rgx.Matches(b);
        for (int i = 0; i < ma.Count; ++i)
        {
            int ret = ma[i].Groups[1].Value.CompareTo(mb[i].Groups[1].Value);
            if (ret != 0)
                return ret;

            ret = int.Parse(ma[i].Groups[2].Value) - int.Parse(mb[i].Groups[2].Value);
            if (ret != 0)
                return ret;
        }

        return 0;
    });
}

static void Main(string[] args)
{
    string[] ar = new string[] { "a99.txt", "b98.txt", "b100.txt" };

    NumericalSort(ar);

    foreach (var a in ar)
        Console.WriteLine(a);
}

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08-30 05:40