在第n次出现的字符处剪切一个字符串

问题描述

我想要做的是获取一个字符串，例如 this.those.that ，并从字符的第n个匹配项中获取子字符串。因此，从字符串的开头到的第二次出现。将返回 this.those 。同样，从第二次出现。到字符串末尾将返回那个。对不起，如果我的问题有雾，那就不容易解释了。另外，请不要建议制作额外的变量，结果将是字符串而不是数组。

What I want to do is take a string such as this.those.that and get a substring to or from the nth occurrence of a character. So, from the start of the string to the 2nd occurrence of . would return this.those. Likewise, from the 2nd occurrence of . to the end of the string would return that. Sorry if my question is foggy, it's not that easy to explain. Also, please do not suggest making extra variables, and the result will be in a string and not an array.

推荐答案

你可以没有数组就可以做到，但是需要更多的代码并且可读性更低。

You could do it without arrays, but it would take more code and be less readable.

通常，您只想使用尽可能多的代码来完成工作，这也提高了可读性。如果您发现此任务正在成为性能问题（基准测试），然后您可以决定开始重构性能。

Generally, you only want to use as much code to get the job done, and this also increases readability. If you find this task is becoming a performance issue (benchmark it), then you can decide to start refactoring for performance.

var str = 'this.those.that',
    delimiter = '.',
    start = 1,
    tokens = str.split(delimiter).slice(start),
    result = tokens.join(delimiter); // those.that

。

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