ruby - 简化字符串乘法连接 | 简化字符串乘法连接

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问题描述

s 是一个字符串，这看起来很啰嗦——我该如何简化它?:

 如果 x === 2z = selif x === 3z = s+selif x === 4z = s+s+selif x === 5z = s+s+s+selif x === 6z = s+s+s+s+s

谢谢

解决方案

这样的事情是最简单且有效的 (如上所见ideone.com):

 puts 'Hello' * 3 # HelloHelloHellos = '去'x = 4z = s * (x - 1)puts z # GoGoGo

API 链接

ruby-doc.org - String: str * integer =>new_str

Copy — 返回一个新的 String，其中包含接收者的整数个副本.

"嗨！"* 3 #=>"呵！呵！呵！"

s is a string, This seems very long-winded - how can i simplify this? :

   if x === 2
      z = s
    elsif x === 3
      z = s+s
    elsif x === 4
      z = s+s+s
    elsif x === 5
      z = s+s+s+s
    elsif x === 6
      z = s+s+s+s+s

Thanks

解决方案

Something like this is the simplest and works (as seen on ideone.com):

puts 'Hello' * 3   # HelloHelloHello

s = 'Go'
x = 4
z = s * (x - 1)
puts z             # GoGoGo

API links

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