如何编写cte从重复表中删除数据

如何编写cte从重复表中删除数据

本文介绍了如何编写cte从重复表中删除数据?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在尝试使用cte从一个表中删除重复的行。但是我从那里得到错误。请帮助我,因为它很紧急。谢谢你。结果和结果是下来..



与cte(cust,fs,rt)

as



select cd.c_cust_code cust,cd.c_fs_code fs

,ROW_NUMBER()over(cd.c_cust_code order by cd.c_fs_code)rt from Tbl_Cust_Div cd

join



选择c_cust_code,c_fs_code,d_date_to

- ,c_div_code
来自Tbl_Cust_Div的
,其中d_date_to ='2016/09/24'

group by c_cust_code,c_fs_code,d_date_to - ,c_div_code

有COUNT(*)> 1

)h on h.c_cust_code = cd .c_cust_code和h.c_fs_code = cd.c_fs_code和h.d_date_to = cd.d_date_to

- 和h.c_div_code = cd.c_div_code





从cte中删除rt<> 1





错误是 -



消息4405,等级16,状态1,行1

视图或函数'cte'不可更新,因为修改会影响多个基表。

I have been trying to delete duplicate rows from one table using cte .but i am getting error from that.please help me since it is urgent.thank u.query and result is ther in down..

with cte(cust,fs,rt)
as
(
select cd.c_cust_code cust,cd.c_fs_code fs
,ROW_NUMBER() over(partition by cd.c_cust_code order by cd.c_fs_code ) rt from Tbl_Cust_Div cd
join
(
select c_cust_code,c_fs_code,d_date_to
--,c_div_code
from Tbl_Cust_Div where d_date_to='2016/09/24'
group by c_cust_code,c_fs_code,d_date_to--,c_div_code
having COUNT(*)>1
)h on h.c_cust_code=cd.c_cust_code and h.c_fs_code=cd.c_fs_code and h.d_date_to=cd.d_date_to
--and h.c_div_code=cd.c_div_code
)

delete from cte where rt<>1


error is-

Msg 4405, Level 16, State 1, Line 1
View or function 'cte' is not updatable because the modification affects multiple base tables.

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08-30 01:27