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问题描述
// USER_REGISTRATION_DB(POJO class)
@Entity
@Table(name="USER_REGISTRATION_DB")
public class UserRegistration_DB {
// this is for primary key
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name="USER-NO")
private int userno;
@Size(min=5, max = 5 ,message="please Enter char followed by NUM")
@NotNull
@Column(name="UUID")
private String uuid;
@Size(min = 2, max = 30,message="Please Enter More than One Character")
@Column(name = "FIRST_NAME")
private String first_name;
@Column(name = "LAST_NAME")
private String last_name;
@NotNull(message="Please Enter Correct DOB")
@DateTimeFormat(pattern="dd/mm/yyyy")
@Past
@Column(name = "DATE_OF_BIRTH")
private Date date_of_birth;
//@NotNull(message="Please Enter your Customer_Id")
@Column(name="AGE")
private String age;
//@NotEmpty(message="Please Enter your Email")
@Size(min = 12, max = 40,message="Please Enter More than Eleven Characters")
@Email(message="Please Enter Valid Email ID")
@Column(name = "EMAIL", unique=true)
private String email;
//@NotNull(message="Please Enter your Password")
@Size(min = 6, max = 30,message="Please Enter more than 6 Characters")
@Column(name = "PASSWORD")
private String password;
@NotNull(message="Please Enter mobile number")
@Column(name = "MOBILE")
private String mobile;
//@NotEmpty(message="Please Enter your Username")
@Size(min = 3, max = 40,message="Please Enter More than 2 Characters")
@Column(name="USERNAME")
private String username;
//@NotNull(message="Please Enter your streetName")
@Size(min = 2, max = 60,message="Please Enter More than 1 Characters")
@Column(name="ADDRESS")
private String address;
//@NotNull(message="Please Enter your Customer_Id")
@Column(name="V_ID")
private String vid;
// this my DAO class implementation
public void saveNewUser(
UserRegistration_DB userRegistration_DB)throws IOException
{
System.out.println("In User registration DB DAO class::::::::::"+userRegistration_DB.getFirst_name()+" "+userRegistration_DB.getUuid());
Session session = getSession(); //creating session
session.beginTransaction(); //begin transaction for the session.
Query query = session.createQuery("UPDATE UserRegistration_DB set first_name =:firstname,last_name =:lastname,username =:username,date_of_birth =:dob,Email =:email,password =:password,Mobile =:mobile,Address =:address,Age =:age" +
" Uuid =:uuid ");
query.setParameter("firstname",userRegistration_DB.getFirst_name());
query.setParameter("lastname",userRegistration_DB.getLast_name());
query.setParameter("mobile",userRegistration_DB.getMobile());
query.setParameter("email",userRegistration_DB.getEmail());
query.setParameter("dob",userRegistration_DB.getDate_of_birth());
query.setParameter("age",userRegistration_DB.getAge());
query.setParameter("password",userRegistration_DB.getPassword());
query.setParameter("username",userRegistration_DB.getUsername());
query.setParameter("uuid",userRegistration_DB.getUuid());
query.setParameter("address",userRegistration_DB.getAddress());
query.setParameter("vid",userRegistration_DB.getVid());
int user = query.executeUpdate();
session.save(userRegistration_DB);
System.out.println("user values are ::::::::::::::::::"+user);
session.getTransaction().commit(); //here transaction complete with commit the data in db.
session.close();
//session close
}
// this is controller class
//UserRegistrationController.java
@RequestMapping(value={"/signup"},method=RequestMethod.POST)
public String saveRegAction(@ModelAttribute("signup") @Validated UserRegistration_DB userRegistration_DB,BindingResult bindingResult,Model model,HttpSession session,HttpServletResponse servletResponse) throws Exception
{
System.out.println("the object is:" + model);
if(bindingResult.hasErrors())
{
logger.info("user details==========="+userRegistration_DB.getFirst_name()+""+userRegistration_DB.getLast_name()+""+userRegistration_DB.getMobile()+""+userRegistration_DB.getEmail()+""+
userRegistration_DB.getDate_of_birth()+""+userRegistration_DB.getAge()+""+userRegistration_DB.getPassword()+""+userRegistration_DB.getUsername()+""+userRegistration_DB.getAddress());
logger.info("Returning home.jsp page");
model.addAttribute("login", new Login());
model.addAttribute("user", new UserRegistration_DB());
return "signup";
}
//registerService.saveRegister(register);
userRegistrationService.saveNewUser(userRegistration_DB);
session.setAttribute("userRegistration_DB", userRegistration_DB);
return "main";
}
// error am getting is
// am Using Mysql DB
// User_REGISTRATION_DB is not being created
/* HHH000388:不成功:创建表USER_REGISTRATION_DB(USER-NO整数不为null，ADDRESS varchar(60)，AGE varchar(255)，DATE_OF_BIRTH日期时间不为null，EMAIL varchar(40)，FIRST_NAME varchar(30)，LAST_NAME varchar(255)，MOBILE varchar(255)不为null，PASSWORD varchar(30)，USERNAME varchar(40)，UUID varchar(5)不为null，V_ID varchar(255)，主键(USER-NO))
/* HHH000388: Unsuccessful: create table USER_REGISTRATION_DB (USER-NO integer not null, ADDRESS varchar(60), AGE varchar(255), DATE_OF_BIRTH datetime not null, EMAIL varchar(40), FIRST_NAME varchar(30), LAST_NAME varchar(255), MOBILE varchar(255) not null, PASSWORD varchar(30), USERNAME varchar(40), UUID varchar(5) not null, V_ID varchar(255), primary key (USER-NO))
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-NO integer not null, ADDRESS varchar(60), AGE varchar(255), DATE_OF_BIRTH datet' at line 1 */
推荐答案
在列名称中使用连字符似乎是Hibernate的已知问题.
Using hyphens in column names appears to be a known problem with Hibernate.
在JPA 1.0中，解决方法是使用反引号对列名进行转义:
In JPA 1.0 the workaround is to escape the column name with backticks:
// this is for primary key
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name = "`USER-NO`")
private int userno;
在JPA 2.0和更高版本中，您可以简单地在列名两边加上引号，例如
In JPA 2.0 and later, you can simply place quotes around the column name, e.g.
@Column(name = "\"USER-NO\"")
参考:
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