本文介绍了Entity Framework 6 迁移是否可以包含围绕脚本的事务?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
很简单的问题,我在实体框架6中使用迁移,和命令一样
Very simple question, i am using migrations in entity framework 6, and like the command
update-database -script
但是有没有一种方法可以生成脚本但将其与事务包装在一起?
But is there a way of generating the script but have it wrapped with a transaction?
问题是如果脚本失败,我必须取消它
Problem is that if the script fails, i have to unpick it
推荐答案
这是我只在发布模式下用来生成脚本的:
This is what I'm using only on release mode to generate the scripts:
public class MigrationScriptBuilder : SqlServerMigrationSqlGenerator
{
#if !DEBUG
protected override void Generate(SqlOperation sqlOperation)
{
Statement("GO");
base.Generate(sqlOperation);
Statement("GO");
}
public override IEnumerable<MigrationStatement> Generate(IEnumerable<MigrationOperation> migrationOperations, string providerManifestToken)
{
yield return new MigrationStatement {Sql = "BEGIN TRAN"};
foreach (var migrationStatement in base.Generate(migrationOperations, providerManifestToken))
{
yield return migrationStatement;
}
yield return new MigrationStatement {Sql = "COMMIT TRAN"};
}
#endif
}
您应该在 DatabaseMigrationsConfiguration
中连接它.示例:
You should wire that in your DatabaseMigrationsConfiguration
. Example:
public sealed class DatabaseMigrationsConfiguration : DbMigrationsConfiguration<DatabaseContext>
{
public DatabaseMigrationsConfiguration()
{
SetSqlGenerator("System.Data.SqlClient", new MigrationScriptBuilder());
}
}
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