真相表 - 援助

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问题描述

我对作业有疑问。问题基本上如下：
有两个整数变量，例如A和B.这两个整数都包含数据。
使用真值表，如果有的话，以下IF语句测试相当于：

  if（ ！（A == 60&& B == 40））
 
  -  if（A！= 60 || B！= 40）
  -  if（A == 60&） ;&（！（B == 40）））

我将如何解决这个问题。任何建议将不胜感激。我认为我必须创建一个包含三列的表 - 一个名为A，另一个名为B，第三列名为RESULT（是或否）。

语句： if（！（A == 60&& B == 40）） - 我不确定如何阅读部分if（！。换句话说，部分 A == 60& B&= 40 告诉我A基本上必须等于60 AND在同一时间B必须等于40.之后我感到困惑。任何帮助/建议请将不胜感激。

谢谢
Chris

解决方案

这与Java本身无关。是的，您可以通过编写真值表来解决。！ 表示逻辑否定或不，或者您甚至可以将其视为相反。就我个人而言，我发现它对建立特定真值表的所有部分。

  a | b |！b | a& b | a&！ b | ！（a& b）
 -------------------------------------------- -------------------------------------------- 
 A = 60 | B = 40 | ！（B = 40）| （A = 60& B = 40）| A = 60& ！（B = 40）| ！（A = 60& B = 40）
 T | T | F | T | F | F 
 T | F | T | F | T | T 
 F | T | F | F | F | T 
 F | F | T | F | F | T

您应该注意您的特定示例受

  P是A = 60 
 Q是B = 40 $ b $b¬是！ $ b $b∧是&& $ b $b∨是||

so ...

！（A&& B）与真的相同！A || ！B

真值表告诉您解决该问题需要了解的其余部分。

I have a question for an assignment. The questions is basically the following:There are 2 integer variables say A and B. Both these integers contain data.Using a truth table, which, if any, of the following IF statement tests is equivalent to:

if (!(A == 60 && B == 40))

 -   if (A != 60 || B != 40)
 -  if (A == 60 && (!(B == 40)))

How would i tackle this please. Anything advice would be appreciated. I think that I have to create a table with three columns - one called A, another B, and the third column called RESULT (YES OR NO).

The statement: if (!(A == 60 && B == 40)) - I am not to sure how to read the part if (!. In other words, the part A == 60 && B == 40 is telling me essentially that A must equal 60 AND AT THE SAME TIME B must equal 40. Following that I am confused. Any help/advise please would be appreciated.

ThanksChris

解决方案

This really has nothing to do with Java per se. Yes, you can solve by writing the truth tables. The ! means logical negation or not or you may even think of it as opposite. Personally, I find it helpful to establish all the parts of a particular truth table.

   a    |   b    |    !b     |       a & b       |      a & !b        |      !(a & b)
 ----------------------------------------------------------------------------------------
 A = 60 | B = 40 | !(B = 40) | (A = 60 & B = 40) | A = 60 & !(B = 40) | !(A = 60 & B = 40)
   T    |   T    |     F     |         T         |        F           |          F
   T    |   F    |     T     |         F         |        T           |          T
   F    |   T    |     F     |         F         |        F           |          T
   F    |   F    |     T     |         F         |        F           |          T

You should note your particular example is subject to one of De Morgan's Laws.

P is A = 60
Q is B = 40
¬ is !
∧ is &&
∨ is ||

so...

!(A && B) is really the same as !A || !B

The truth table tells you the rest you need to know to solve that problem.

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