问题描述
我知道之前已经有人问过这个问题,但是就我的情况而言,我似乎无法弄清楚为什么会抛出这个问题
I know this has been asked before, but for my circumstance, I can't seem to figure out why this is being thrown
当我尝试运行计算时,从控制台收到此错误:
When I try to run my calculations, I am given this error from my console:
ValueError:以10为底的int()的无效文字:''
并且说它来自
File "/var/sites/live_mbpathways/moneybroker/apps/investments/ajax.py", line 30, in calc_cdic
investments = Investment.objects.all().filter(plan = plan, financial_institution=fiid, maturity_date__gte = now).order_by('maturity_date').exclude(id=investment_id)
有人知道为什么会这样吗?
Does anyone know why this could be happening?
这里是该代码所在的我的ajax.py:
Here is my ajax.py where that code is located:
@login_required
@moneybroker_auth
@csrf_exempt
def calc_cdic(request, plan, investment_id=None, *args, **kwargs):
from investments.models import Investment
from financial_institutions.models import FinancialInstitution
from profiles.models import Profile
from plans.models import Plan
from datetime import datetime
now = datetime.now()
json = {}
data = request.POST
if request.is_ajax():
total = 0
fiid = data.get('financial_institution')
amt = data.get('amount') or 0
pay_amt = data.get('pay_amount') or 0
mat_amt = data.get('maturity_amount') or 0
investments = Investment.objects.all().filter(plan = plan, financial_institution=fiid, maturity_date__gte = now).order_by('maturity_date').exclude(id=investment_id)
for i in investments:
total += i.maturity_amount
print total
json['total'] = float(str(total))
json['amt'] = float(str(amt))
json['pay_amt'] = float(str(pay_amt))
json['mat_amount'] = float(str(mat_amt))
json['fiid'] = fiid
print json
return HttpResponse(simplejson.dumps(json), mimetype='application/json')
推荐答案
int()函数引发异常,因为您尝试转换的不是数字.
The int() function is throwing an exception because you are trying to convert something that is not a number.
我建议您考虑使用调试打印语句来找出最初的计划和fiid以及它们如何更改.
I suggest that you might consider using debugging print statements to find out what plan's and fiid's are initally and how they change.
您可以做的另一件事是使用try/catch包装对int()的调用
Another thing you can do is wrap the call to int() using try/catch
val='a'
try:
int_val = int(val)
except ValueError:
print("Failure w/ value " + val)
这篇关于获取ValueError:以10为底的int()的无效文字:''错误,不知道为什么的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!