Calloc内部函数

问题描述

看着刚刚问过的这个问题:指向静态变量的指针的不便那样做会被认为是不好的做法吗?

Looking at this question that has just been asked: Inconveniences of pointers to static variables would doing something like this be considered bad practice, then?

char* strpart(char* string, int start, int count)
{
    char* strtemp;
    int i = 0; int j = 0;
    int strL = strlen(string);

    if ( count == 0 )
    {
        count = strL;
    }

    strtemp = (char*) calloc((count + 1), sizeof(char));
    for ( i = start; i < (start+count); i++ )
    {
        strtemp[j] = string[i];
        j++;
    }
    return strtemp;
}

很抱歉，它写得很快，但是基本原理是-当在函数内部不使用静态缓冲区时，在函数内部分配内存是不好的做法吗?我想是因为它不会被释放，对吗?以为我应该问.

Sorry it's written quickly, but the basic principle is - when NOT using a static buffer inside a function is it bad practice to assign memory inside a function? I assume so because it wouldn't be freed, would it? Thought I ought to ask though.

推荐答案

这不错，但很容易造成内存泄漏(调用者必须记住要释放内存).

It's not bad pratice but it can easily create memory leaks (the callers have to remember to free the memory).

我想做的一件事是使用命名约定来指示可以分配哪些函数.例如，我要将该函数命名为:

One thing I like to do is use a naming convention to indicate what functions can allocate. For example, I'd name that function:

char* strpart_alloc(char* string, int start, int count)

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