如何访问链表数组?

问题描述

我使用.也就是说，我已经完成:

I've created an array of LinkedList of Connection objects using the second answer from here. That is, I've done:

LinkedList< Connection> []映射=(LinkedList< Connection> [])new LinkedList [count];

但是，我对如何访问数组的每个元素(即每个 LinkedList)并创建一个新节点感到困惑.现在，我有:

However, I am confused as to how to access each element of the array (ie each LinkedList) and create a new node. Right now, I have:

for (int j = 0; j < numOfConnections; j++) {
    map[j].add(new Connection(s.next(), s.nextDouble(), s.next()));
}

但是我认为这只会向数组的每个LinkedList元素添加一个单个新节点.我想循环遍历并将 numOfConnections 个节点添加到每个 LinkedList元素.例如， map [0] 中的3个节点， map [1] 中的5个节点， map [2] 中的2个节点，等等.

But I think this would only add a single new node to each LinkedList element of the Array. I want to loop through and add numOfConnections amount of nodes to each LinkedList element. For example, 3 nodes in map[0], 5 nodes in map[1], 2 nodes in map[2], etc.

推荐答案

在您的示例中，如果 numOfConnections，则"map [0]中有3个节点，map [1]中有5个节点，map [2]中有2个节点"是您要映射到要添加的列表的要添加到LinkedList [k]的值的数量吗?例如:numOfConnections [] = {3，5，2};

On your example "3 nodes in map[0], 5 nodes in map[1], 2 nodes in map[2]" if numOfConnections is the amount of values you want to add to your LinkedList[k] shoudnt you map which list to add ? eg.: numOfConnections[] = {3, 5, 2};

for ( int k = 0; k < numOfConnections.length; k++ )
{
    if (map[k] == null) map[k] = new LinkedList<Connection>();

    for (int j = 0; j < numOfConnections[k]; j++)
    {
        map[k].add(new Connection(s.next(), s.nextDouble(), s.next()));
    }
}

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