Fortran数组排名为matmul内部

Fortran数组排名为matmul内部

本文介绍了Fortran数组排名为matmul内部的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

以下链接明确指出,gfortran期望输入

您可以使用 RESHAPE c $ c> MATMUL 会像:

 程序暂存
real(kind = 8 ):: A(10)=(/ 0,1,2,3,4,5,6,7,8,9 /)
real(kind = 8):: B(10)=(/ 0,1,2,3,4,5,6,7,8,9 /)
real(kind = 8):: C(10,10)
print *,rank(A) ,等级(B)
C = matmul(RESHAPE(A,(/ 10,1 /)),RESHAPE(B,(/ 1,10 /)))
WRITE(*,(10F7 .2))C
结束程序暂存


The following link https://gcc.gnu.org/onlinedocs/gcc-5.4.0/gfortran/MATMUL.html clearly states that gfortran expects matrices input to matmul to be of rank 1 OR 2. However the following snippet wont compile:

Program scratch
  real(kind=8) :: A(10)=(/0,1,2,3,4,5,6,7,8,9/)
  real(kind=8) :: B(10)=(/0,1,2,3,4,5,6,7,8,9/)
  real(kind=8) :: C(10,10)
  print *,rank(A),rank(B)
  C=matmul(A,B)
End Program scratch

gfortran gives the error:

$gfortran scratch.f90
scratch.f90:6:13:

   C=matmul(A,B)
         1
Error: ‘matrix_b’ argument of ‘matmul’ intrinsic at (1) must be of rank 2

My gfortran is 5.4.0 (compatible with the link above). Am I doing something really stupid?

解决方案

You can use RESHAPE to get them into a form MATMUL will like:

Program scratch
  real(kind=8) :: A(10)=(/0,1,2,3,4,5,6,7,8,9/)
  real(kind=8) :: B(10)=(/0,1,2,3,4,5,6,7,8,9/)
  real(kind=8) :: C(10,10)
  print *,rank(A),rank(B)
  C = matmul( RESHAPE(A,(/10,1/)), RESHAPE(B,(/1,10/)) )
  WRITE(*,"(10F7.2)") C
End Program scratch

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08-29 06:12