php相对时间问题

问题描述

我有这个函数来计算自某一日期以来所经过的相对时间，

  function nicetime（$ date）{
 if（empty（$ date））{
 return没有提供日期; 
} 
 
 $ periods = array（second，minute，hour，day，week，month，year，decade） ; 
 $ lengths = array（60，60，24，7，4.35，12，10）; 
 
 $ now = time（）; 
 $ unix_date = strtotime（$ date）; 
 
 //检查日期的有效性
 if（empty（$ unix_date））{
 returnBad date; 
} 
 
 //是未来日期或过去日期
 if（$ now> $ unix_date）{
 $ difference = $ now  -  $ unix_date; 
 $ tense =ago; 
 
} else {
 $ difference = $ unix_date  -  $ now; 
 $ tense =from now; 
} 
 
 for（$ j = 0; $ difference> = $ lengths [$ j]& $ j< count（$ lengths）-1; $ j ++） {
 $ differences / = $ lengths [$ j]; 
} 
 
 $ difference = round（$ difference）; 
 
 if（$ difference！= 1）{
 $ periods [$ j]。=s; 
} 
 
 return$ difference $ periods [$ j] {$ tense}; 
} 
  

我传递函数的日期为2011-01-16 12： 30，但是我得到不好的日期返回，这意味着 $ unix_date 是空的，但是如果我死在函数中，我得到 $ date 传递给函数，但是它返回一个（在它之前，下面是我如何调用该方法。

echo nicetime（date（'Y：m：d G：i'，$ a ['created_at']））

方案

  echo nicetime（2011-01-16 12:30）; 
   
 
对我来说很合适我建议你确保
  $ a ['created_at '] 
  
给你你的东西。 
 
  $ dtDate = $ a ['created_at']; 
 $ strDate = date（'Y：m：d G：i'，$ dtDate） ; 
 echo $ strDate; 
 echo nicetime（$ strDate）; 
  
 
 
肯定$ strDate是你认为的。
 
I have this function to work out the relative time that has elapsed since a certain date,
function nicetime($date) {
    if(empty($date)) {
        return "No date provided";
    }

    $periods         = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
    $lengths         = array("60","60","24","7","4.35","12","10");

    $now             = time();
    $unix_date         = strtotime($date);

       // check validity of date
    if(empty($unix_date)) {
        return "Bad date";
    }

    // is it future date or past date
    if($now > $unix_date) {
        $difference     = $now - $unix_date;
        $tense         = "ago";

    } else {
        $difference     = $unix_date - $now;
        $tense         = "from now";
    }

    for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
        $difference /= $lengths[$j];
    }

    $difference = round($difference);

    if($difference != 1) {
        $periods[$j].= "s";
    }

    return "$difference $periods[$j] {$tense}";
}
I am passing the function a date as "2011-01-16 12:30", however I am getting bad date returned which means that $unix_date is empty however if I die in the function I get the $date that is passed to the function however it gets return with a ( before it, below is how I am calling the method.
echo nicetime(date('Y:m:d G:i', $a['created_at']))
 解决方案 
echo nicetime("2011-01-16 12:30");
works fine for me.  I would suggest you ensure
 $a['created_at']
is giving you what you thing it is.  Maybe try
$dtDate = $a['created_at'];
$strDate = date('Y:m:d G:i', $dtDate );
echo $strDate;
echo nicetime($strDate);
Make sure $strDate is what you think it is.
                        
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