问题描述
我有两个高斯图:
x = np.linspace(-5,9,10000)
plot1=plt.plot(x,mlab.normpdf(x,2.5,1))
plot2=plt.plot(x,mlab.normpdf(x,5,1))
,我想找到两条曲线相交的点.有没有办法做到这一点?特别是我想找到它们相交处的x坐标的值.
and I want to find the point at where the two curves intersect. Is there a way of doing this? In particular I want to find the value of the x-coordinate where they meet.
推荐答案
您要查找x,以使两个高斯函数具有相同的高度.(即相交)
You want to find the x's such that both gaussian functions have the same height.(i.e intersect)
您可以通过将两个高斯函数相等并求解x来实现.最后,您将得到一个二次方程,其系数与高斯均值和方差有关.这是最终结果:
You can do so by equating two gaussian functions and solve for x. In the end you will get a quadratic equation with coefficients relating to the gaussian means and variances. Here is the final result:
import numpy as np
def solve(m1,m2,std1,std2):
a = 1/(2*std1**2) - 1/(2*std2**2)
b = m2/(std2**2) - m1/(std1**2)
c = m1**2 /(2*std1**2) - m2**2 / (2*std2**2) - np.log(std2/std1)
return np.roots([a,b,c])
m1 = 2.5
std1 = 1.0
m2 = 5.0
std2 = 1.0
result = solve(m1,m2,std1,std2)
输出为:
array([ 3.75])
您可以绘制找到的交叉点:
You can plot the found intersections:
x = np.linspace(-5,9,10000)
plot1=plt.plot(x,mlab.normpdf(x,m1,std1))
plot2=plt.plot(x,mlab.normpdf(x,m2,std2))
plot3=plt.plot(result,mlab.normpdf(result,m1,std1),'o')
情节将是:
如果您的高斯人有多个交集,那么代码也会找到所有的交集(例如m1 = 2.5,std1 = 3.0,m2 = 5.0,std2 = 1.0):
If your gaussians have multiple intersections, the code will also find all of them(say m1=2.5, std1=3.0, m2=5.0, std2=1.0):
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