问题描述
我想将pandas cut功能应用于包含NaN的系列.理想的行为是将非NaN元素存储到桶中，并为NaN元素返回NaN.
I would like to apply the pandas cut function to a series that includes NaNs. The desired behavior is that it buckets the non-NaN elements and returns NaN for the NaN-elements.
import pandas as pd
numbers_with_nan = pd.Series([3,1,2,pd.NaT,3])
numbers_without_nan = numbers_with_nan.dropna()
对于没有NaN的系列，裁剪效果很好:
The cutting works fine for the series without NaNs:
pd.cut(numbers_without_nan, bins=[1,2,3], include_lowest=True)
0 (2.0, 3.0]
1 (0.999, 2.0]
2 (0.999, 2.0]
4 (2.0, 3.0]
当我剪切包含NaN的序列时，元素3正确返回为NaN，但是最后一个元素分配了错误的bin:
When I cut the series that contains NaNs, element 3 is correctly returned as NaN, but the last element gets the wrong bin assigned:
pd.cut(numbers_with_nan, bins=[1,2,3], include_lowest=True)
0 (2.0, 3.0]
1 (0.999, 2.0]
2 (0.999, 2.0]
3 NaN
4 (0.999, 2.0]
如何获得以下输出?
0 (2.0, 3.0]
1 (0.999, 2.0]
2 (0.999, 2.0]
3 NaN
4 (2.0, 3.0]
推荐答案
这很奇怪.问题不是pd.NaT，而是您的系列具有object dtype而不是常规数字系列的事实，例如float，int.
This is strange. The problem isn't pd.NaT, it's the fact your series has object dtype instead of a regular numeric series, e.g. float, int.
一个快速的解决方法是通过fillna用np.nan替换pd.NaT.这会触发从object到float64 dtype的系列转换，也可能导致更好的性能.
A quick fix is to replace pd.NaT with np.nan via fillna. This triggers series conversion from object to float64 dtype, and may also lead to better performance.
s = pd.Series([3, 1, 2, pd.NaT, 3])
res = pd.cut(s.fillna(np.nan), bins=[1, 2, 3], include_lowest=True)
print(res)
0 (2, 3]
1 [1, 2]
2 [1, 2]
3 NaN
4 (2, 3]
dtype: category
Categories (2, object): [[1, 2] < (2, 3]]
更通用的解决方案是事先将其显式转换为数字:
A more generalized solution is to convert to numeric explicitly beforehand:
s = pd.to_numeric(s, errors='coerce')
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