如何在BigQuery中使用线性插值法填充不规则的缺失值

如何在BigQuery中使用线性插值法填充不规则的缺失值

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问题描述

我有不规则地缺少值的数据,我想使用BigQuery Standard SQL使用线性插值以一定间隔转换它.

具体来说,我有这样的数据:

 #数据不规则丢失+ ------ + ------- +|时间|值|+ ------ + ------- +|1 |3.0 ||5 |5.0 ||7 |1.0 ||9 |8.0 ||10 |4.0 |+ ------ + ------- + 

,我想按以下方式转换此表:

 #以1的间隔插值+ ------ + -------------------- +|时间|value_interpolated |+ ------ + -------------------- +|1 |3.0 ||2 |3.5 ||3 |4.0 ||4 |4.5 ||5 |5.0 ||6 |3.0 ||7 |1.0 ||8 |4.5 ||9 |8.0 ||10 |4.0 |+ ------ + -------------------- + 

有什么聪明的解决方案吗?

补充:此问题类似于

I have data which has missing values irregulaly, and I'd like to convert it with a certain interval with liner interpolation using BigQuery Standard SQL.

Specifically, I have data like this:

# data is missing irregulary
+------+-------+
| time | value |
+------+-------+
|    1 | 3.0   |
|    5 | 5.0   |
|    7 | 1.0   |
|    9 | 8.0   |
|   10 | 4.0   |
+------+-------+

and I'd like to convert this table as follows:

# interpolated with interval of 1
+------+--------------------+
| time | value_interpolated |
+------+--------------------+
|    1 | 3.0                |
|    2 | 3.5                |
|    3 | 4.0                |
|    4 | 4.5                |
|    5 | 5.0                |
|    6 | 3.0                |
|    7 | 1.0                |
|    8 | 4.5                |
|    9 | 8.0                |
|   10 | 4.0                |
+------+--------------------+

Any smart soluton for this?

Supplement: this question is similar to this question in stackoverflow but different in that the data is missing irregulaly.

Thank you.

解决方案

Below is for BigQuery Standard SQL

#standardSQL
select time,
  ifnull(value, start_value + (end_value - start_value) / (end_tick - start_tick) * (time - start_tick)) as value_interpolated
from (
  select time, value,
    first_value(tick ignore nulls) over win1 as start_tick,
    first_value(value ignore nulls) over win1 as start_value,
    first_value(tick ignore nulls) over win2 as end_tick,
    first_value(value ignore nulls) over win2 as end_value,
  from (
    select time, t.time as tick, value
    from (
      select generate_array(min(time), max(time)) times
      from `project.dataset.table`
    ), unnest(times) time
    left join `project.dataset.table` t
    using(time)
  )
  window win1 as (order by time desc rows between current row and unbounded following),
  win2 as (order by time rows between current row and unbounded following)
)

if to apply to sample data from your question - output is

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08-29 05:02