问题描述
我在touples列表清单得到了一些数据。我的任务是使从热图。
作为在C＃中的新手，我已经搜查了网，发现解决所画在DataGridView中的元素这一任务的一种方式，但我不明白，怎么办呢。
所以，我有Touples的列表：
I've got some data in List of List of touples. My task is to make a heatmap from that.Being newbie in C#, I've searched the net and found a way of solving this task by painting elements in DataGridView, but I don't understand, how to do it.So,I've got a list of Touples:
using SpikeDataPacket = List<Tuple<double, double>>;
这是我加载网格内数据的方式：
This is the way I load data inside the grid:
public HeatForm(List<SpikeDataPacket> list)
{
SpikeList = list;
InitializeComponent();
var bindstim = new BindingList<SpikeDataPacket>(SpikeList);
var stimsource = new BindingSource(bindstim, null);
heatMap.DataSource = stimsource;
}
但是，这显示与容量和在DataGridView内部计数，而不是数据表。
另外，我发现数颜色的方式，但不知道如何使用它：
But this displays a table with "capacity" and "count" inside the DataGridView, but not the data.Also, I've found the way to count the color, but don't know, how to apply it:
private Color HeatMapColor(double value, double min, double max)
{
Color firstColour = Color.RoyalBlue;
Color secondColour = Color.LightSkyBlue;
// Example: Take the RGB
//135-206-250 // Light Sky Blue
// 65-105-225 // Royal Blue
// 70-101-25 // Delta
int rOffset = Math.Max(firstColour.R, secondColour.R);
int gOffset = Math.Max(firstColour.G, secondColour.G);
int bOffset = Math.Max(firstColour.B, secondColour.B);
int deltaR = Math.Abs(firstColour.R - secondColour.R);
int deltaG = Math.Abs(firstColour.G - secondColour.G);
int deltaB = Math.Abs(firstColour.B - secondColour.B);
double val = (value - min) / (max - min);
int r = rOffset - Convert.ToByte(deltaR * (1 - val));
int g = gOffset - Convert.ToByte(deltaG * (1 - val));
int b = bOffset - Convert.ToByte(deltaB * (1 - val));
return Color.FromArgb(255, r, g, b);
}
感谢你在前进！
推荐答案
我想我会有所不同解决这个问题。
I think I would tackle the problem somewhat differently.
- 我要开始的没有是
数据绑定。无论是元组结构名单的名单，也不是双到颜色映射适合于井数据绑定。 - 我也不能确定你的颜色映射算法..
- I would start without using
DataBinding. Neither the List of List of Tuple structure nor the mapping of a double to aColorlends itself to well toDataBinding. - I'm also not sure about your color mapping algorithm..
要填写数据到一个DataGridView DGV我用一个简单的程序，该程序首先prepares的DGV，然后描绘了细胞：
To fill the data into a DataGridView DGV I use a simple routine, which first prepares the DGV and then paints the Cells:
void fillData()
{
int maxRow = data.Count;
int maxCol = data[0].Count;
double factor = 1.0;
DGV.RowHeadersVisible = false;
DGV.ColumnHeadersVisible = false;
DGV.AllowUserToAddRows = false;
DGV.AllowUserToOrderColumns = false;
DGV.CellBorderStyle = DataGridViewCellBorderStyle.None;
//..
int rowHeight = DGV.ClientSize.Height / maxRow - 1;
int colWidth = DGV.ClientSize.Width / maxCol - 1;
for (int c = 0; c < maxRow; c++) DGV.Columns.Add(c.ToString(), "");
for (int c = 0; c < maxRow; c++) DGV.Columns[c].Width = colWidth;
DGV.Rows.Add(maxRow);
for (int r = 0; r < maxRow; r++) DGV.Rows[r].Height = rowHeight;
List<Color> baseColors = new List<Color>(); // create a color list
baseColors.Add(Color.RoyalBlue);
baseColors.Add(Color.LightSkyBlue);
baseColors.Add(Color.LightGreen);
baseColors.Add(Color.Yellow);
baseColors.Add(Color.Orange);
baseColors.Add(Color.Red);
List<Color> colors = interpolateColors(baseColors, 1000);
for (int r = 0; r < maxRow; r++)
{
for (int c = 0; c < maxRow; c++)
{
DGV[r,c].Style.BackColor =
colors[ Convert.ToInt16( data[r][c].Item2 * factor)];
}
}
}
您会wnat改变一些东西，特别是底座的颜色和你想要得到的，这取决于你的价值观的颜色数也从一个双精度值到整数索引的映射！
You would wnat to change a few things, especially the base colors and the number of colors you want to get, depending on your values but also the mapping from a double value to a integer index!
下面是创建内插颜色的列表的功能。这需要几个基础的颜色和长度N和返回n插值颜色。这使得映射简单灵活。
Here is the function to create a list of interpolated colors. It takes a few base colors and a length N and returns N interpolated colors. This makes the mapping simple and flexible..
List<Color> interpolateColors(List<Color> stopColors, int count)
{
SortedDictionary<float, Color> gradient = new SortedDictionary<float, Color>();
for (int i = 0; i < stopColors.Count; i++)
gradient.Add(1f * i / (stopColors.Count-1), stopColors[i]);
List<Color> ColorList = new List<Color>();
using (Bitmap bmp = new Bitmap(count, 1))
using (Graphics G = Graphics.FromImage(bmp))
{
Rectangle bmpCRect = new Rectangle(Point.Empty, bmp.Size);
LinearGradientBrush br = new LinearGradientBrush
(bmpCRect, Color.Empty, Color.Empty, 0, false);
ColorBlend cb = new ColorBlend();
cb.Positions = new float[gradient.Count];
for (int i = 0; i < gradient.Count; i++)
cb.Positions[i] = gradient.ElementAt(i).Key;
cb.Colors = gradient.Values.ToArray();
br.InterpolationColors = cb;
G.FillRectangle(br, bmpCRect);
for (int i = 0; i < count; i++) ColorList.Add(bmp.GetPixel(i, 0));
br.Dispose();
}
return ColorList;
}
我的测试数据进行了这样的创建：
My test data were created like this:
List<List<Tuple<double,double>>> data = new List<List<Tuple<double,double>>>();
Random R = new Random();
void createData(int maxRow, int maxCol)
{
for (int c = 0; c < maxRow; c++)
{
data.Add(new List<Tuple<double, double>>());
for (int r = 0; r < maxRow; r++)
{
data[c].Add(new Tuple<double, double>(c, Math.Min(999, R.Next(r*c))));
}
}
}
和我使用它是这样的：
private void Form1_Load(object sender, EventArgs e)
{
createData(40, 40);
fillData();
}
下面是一个（相当沉闷）截图：
Here is a (rather boring) screenshot:
一旦你得到了展示，只要你想，你可能需要决定要不要去寻求解决方案的与 数据绑定。我相信，你将需要使用 OwnerDrawing 的单元。一旦你有了单元格中的值，可以使用相同的映射只是这样的：
Once you got the display as you want it, you may want to decide about going for a solution with DataBinding. I believe that you will need to use OwnerDrawing the Cells. Once you have the values in the cells you can use the same mapping simply like this:
private void DGV_CellPainting(object sender, DataGridViewCellPaintingEventArgs e)
{
Color theColor = .....
e.Graphics.Clear(colors[theColor]);
}
这篇关于清单＆LT; T＆GT;＆GT从名单＆LT显示在DataGridView的热图;在C＃中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！