将在函数中创建的图形添加到另一个图形的子图中

问题描述

我创建了两个函数，可以绘制两个特定的图并返回各自的图形:

I created two functions that make two specific plots and returns me the respective figures:

import matplotlib.pyplot as plt

x = range(1,100)
y = range(1,100)

def my_plot_1(x,y):
    fig = plt.plot(x,y)
    return fig

def my_plot_2(x,y):
    fig = plt.plot(x,y)
    return fig

现在，在我的功能之外，我想创建一个具有两个子图的图形并将其添加到我的功能图形中.像这样:

Now, outside of my functions, I want to create a figure with two subplots and add my function figures to it. Something like this:

my_fig_1 = my_plot_1(x,y)
my_fig_2 = my_plot_2(x,y)

fig, fig_axes = plt.subplots(ncols=2, nrows=1)
fig_axes[0,0] = my_fig_1
fig_axes[0,1] = my_fig_2

但是，仅将创建的图形分配给该新图形是行不通的.该函数调用图形，但未在子图中分配该图形.有没有办法将我的功能图放置在另一个图的子图中?

However, just allocating the created figures to this new figure does not work. The function calls the figure, but it is not allocated in the subplot. Is there a way to place my function figure in another figure's subplot?

推荐答案

Eaiser最好将函数传递给 Axes :

Eaiser and better to just pass your function an Axes:

def my_plot_1(x,y,ax):
    ax.plot(x,y)

def my_plot_2(x,y,ax):
    ax.plot(x,y)

fig, fig_axes = plt.subplots(ncols=2, nrows=1)

# pass the Axes you created above
my_plot_1(x, y, fig_axes[0])
my_plot_2(x, y, fig_axes[1])

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